使用递归完成 1 到 100 的累加

[Sunny-117]

No description provided.

[lxy-Jason]

function sum(num){
    if(num === 1) return 1
    return num + sum(num - 1);
}
console.log(sum(100));

[weirong111]

尾递归优化，一行代码解决

function process(cur, total = 0) {
  return cur === 0 ? total : process(cur - 1, total + cur);
}

[CwRv07]

function accumulate(curr, max, total = 0) {
  return curr > max ? total : accumulate(curr + 1, max, total + curr);
}

console.log(accumulate(1,100)); // 5050

[MoYuanJun]

// 直接就是一个循环
const sum = (min, max) => {
  let total = 0

  while(min <= max) {
    total += min
    min+=1
  }
  return total
}

// 递归:  相当于 min + (min + 1) + (min + 1 + 1)……
const sum1 = (min, max) => {
  if (min === max) return min
  return min + sum1(min + 1, max)
}

[fangbw17]

function recursionNum(max = 0, total = 0) {
    return max === 0 ? total : recursionNum(max - 1, total + max)
}

[bearki99]

function process(cur, sum = 0) {
  return cur === 0 ? sum : process(cur - 1, sum + cur);
}
console.log(process(100));

[gocpekfdj]

function f(n){
if(n>100)
return 0;
return n+f(n+1);
}
console.log(f(1));