获取树结构中的name：getName

[Sunny-117]

let data = [
      {
          "name": "1-1",
          "kind": "oo",
          "children": [
              {
                  "name": "2-2",
                  "kind": "ii",

              },
              {
                  "name": "3-3",
                  "children": [
                      {
                          "name": "4-4",
                          "children": [
                              {
                                  "name": '707'
                              }
                          ]
                      }
                  ]
              }
          ]
      },
      {
          "name": "5-5",
      },
      {
          "name": "6-6"
      }
  ]
  function getName(data, key = "name") {
      let result = [];
      if (Array.isArray(data)) {
          for (let item of data) {
              if (item[key]) {
                  result.push(item[key]);
              }
              if (item.children) {
                  result = result.concat(getName(item.children));
              }
          }
          return result;
      } else {
          return result;
      }
  }

  console.log(getName(data))

[kangkang123269]

function getName(data, key = 'name') {
    const result = []
    const dfs = (node) => { 
        for (const p of node) {
            p.name && result.push(p[key])
            p.children && dfs(p.children)
        }
    }
    Array.isArray(data) && dfs(data)
    return result
}

[lesenelir]

function getName(data) {
  let res = [],
      len = data.length

  for (let i = 0; i < len; i++) {
    traversal(data[i])
  }

  return res

  function traversal(node) {
    if (!node) return

    res.push(node.name)
    node.children && node.children.forEach(item => {
      traversal(item)
    })
  }

}