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n个2的n次方之和 #253

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Sunny-117 opened this issue Nov 4, 2022 · 3 comments

Owner

Sunny-117 commented Nov 4, 2022

No description provided.

bearki99 commented Feb 21, 2023

等比数列求和吧

Contributor

veneno-o commented Mar 18, 2023

等比数列求和公式

Sn = a1 * (q**n - 1) / (q - 1)

Liu6625 commented Oct 18, 2023

function sumOfPowers(n) {
  let sum = 0;
  for (let i = 0; i < n; i++) {
    sum += Math.pow(2, i);
  }
  return sum;
}

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