Given a binary tree, you need to compute the length of the diameter of the tree. The diameter of a binary tree is the length of the longestpath between any two nodes in a tree. This path may or may not pass through the root.
Example: Given a binary tree
1
/ \
2 3
/ \
4 5
Return 3, which is the length of the path [4,2,1,3] or [5,2,1,3].
Note: The length of path between two nodes is represented by the number of edges between them.
/**
* Definition for a binary tree node.
* public class TreeNode {
* public var val: Int
* public var left: TreeNode?
* public var right: TreeNode?
* public init(_ val: Int) {
* self.val = val
* self.left = nil
* self.right = nil
* }
* }
*/
class Solution {
func diameterOfBinaryTree(_ root: TreeNode?) -> Int {
var diameter = 0
func maxValue(_ root: TreeNode?) -> Int {
guard let n = root else { return 0 }
let l = maxValue(n.left)
let r = maxValue(n.right)
diameter = max(diameter , l + r)
return max(l, r) + 1
}
_ = maxValue(root)
return diameter
}
}