Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties:
- Integers in each row are sorted from left to right.
- The first integer of each row is greater than the last integer of the previous row.
For example,
Consider the following matrix:
[
[1, 3, 5, 7],
[10, 11, 16, 20],
[23, 30, 34, 50]
]
Given target = 3
, return true
.
class Solution {
func searchMatrix(_ matrix: [[Int]], _ target: Int) -> Bool {
guard !matrix.isEmpty, !matrix[0].isEmpty else { return false }
for y in 0..<matrix.count {
for x in 0..<matrix[y].count {
let v = matrix[y][x]
if v == target {
return true
} else if v > target {
return false
}
}
}
return false
}
}