[27-w6-d2]spiralMatrix.js

//Problem: Write a function that accepts an integer n and returns a n*n spiral matrix.
//Example:
//spiralMatrix(3) // [[1, 2, 3], [8, 9, 4], [7, 6, 5]]

function spiralMatrix(n) {
  let results = []
  for (let i = 0; i < n; i++) {
    results.push([])
  }
  let counter = 1;
  let startColumn = 0;
  let endColumn = n - 1
  let startRow = 0;
  let endRow = n - 1
  
  while (startColumn <= endColumn && startRow <= endRow) {
    for (let i = startColumn; i <= endColumn; i++) {
      results[startRow][i] = counter
      counter++
    }
    startRow++
    for (let i = startRow; i <= endRow; i++) {
      results[i][endColumn] = counter
      counter++
    }
    endColumn--
    for (let i = endColumn; i >= startColumn; i--) {
      results[endRow][i] = counter
      counter++
    }
    endRow--
    for (let i = endRow; i >= startRow; i--) {
      results[i][startColumn] = counter
      counter++
    }
    startColumn++
  }
}