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合并两个排序的链表.md

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68 lines (57 loc) · 1.5 KB

合并两个排序的链表

题目

输入两个单调递增的链表,输出两个链表合成后的链表,当然我们需要合成后的链表满足单调不减规则。

思路

  • 主要思想:比较 + 合并~

代码

/*
/*
public class ListNode {
    int val;
    ListNode next = null;

    ListNode(int val) {
        this.val = val;
    }
}*/
public class Solution {
    public ListNode Merge(ListNode list1,ListNode list2) {
        ListNode head = null;
        
        if (list1 != null && list2 != null) {
            if (list1.val > list2.val) {
                head = list2;
                list2 = list2.next;
            } else {
                head = list1;
                list1 = list1.next;
            }
        } else {
            if (list1 == null) {
                return list2;
            }
            if (list2 == null) {
                return list1;
            }
        }
        
        ListNode result = head;
        
        while (list1 != null && list2 != null) {
            if (list1.val < list2.val) {
                result.next = list1;
                result = list1;
                list1 = list1.next;
            } else {
                result.next = list2;
                result = list2;
                list2 = list2.next;
            }
        }
        
        if (list1 != null) {
            result.next = list1;
        }
        
        if (list2 != null) {
            result.next = list2;
        }
        
        return head;
    }
}