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Program.cs
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Program.cs
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//与LeetCode_102思路一样,将最后结果翻转即可。
using System;
using System.Collections.Generic;
namespace BinaryTreeLevelOrderTraversalII
{
public class TreeNode
{
public int val;
public TreeNode left;
public TreeNode right;
public TreeNode(int val = 0, TreeNode left = null, TreeNode right = null)
{
this.val = val;
this.left = left;
this.right = right;
}
}
class Program
{
static void Main(string[] args)
{
var a = new TreeNode(3);
var b = new TreeNode(9);
var c = new TreeNode(20);
var d = new TreeNode(15);
var e = new TreeNode(7);
a.left = b;
a.right = c;
c.left = d;
c.right = e;
}
public IList<IList<int>> LevelOrderBottom_DFS(TreeNode root)
{
var res = new List<IList<int>>();
DFS(root, 0, res);
res.Reverse();
return res;
}
private void DFS(TreeNode node, int level, List<IList<int>> res)
{
if (node == null) return;
if(res.Count <= level)
res.Add(new List<int>());
res[level].Add(node.val);
DFS(node.left, level + 1, res);
DFS(node.right, level + 1, res);
}
public IList<IList<int>> LevelOrderBottom_BFS(TreeNode root)
{
var res = new List<IList<int>>();
if (root == null) return res;
var queue = new Queue<TreeNode>();
queue.Enqueue(root);
while (queue.Count != 0)
{
var count = queue.Count;
var layer = new List<int>();
while (count != 0)
{
var cur = queue.Dequeue();
layer.Add(cur.val);
if(cur.left != null) queue.Enqueue(cur.left);
if(cur.right != null) queue.Enqueue(cur.right);
count--;
}
res.Add(layer);
}
res.Reverse();
return res;
}
}
}