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103.binary-tree-zigzag-level-order-traversal.js
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103.binary-tree-zigzag-level-order-traversal.js
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/*
* @lc app=leetcode id=103 lang=javascript
*
* [103] Binary Tree Zigzag Level Order Traversal
*
* https://leetcode.com/problems/binary-tree-zigzag-level-order-traversal/description/
*
* algorithms
* Medium (48.15%)
* Likes: 2326
* Dislikes: 103
* Total Accepted: 395.2K
* Total Submissions: 817.9K
* Testcase Example: '[3,9,20,null,null,15,7]'
*
* Given a binary tree, return the zigzag level order traversal of its nodes'
* values. (ie, from left to right, then right to left for the next level and
* alternate between).
*
*
* For example:
* Given binary tree [3,9,20,null,null,15,7],
*
* 3
* / \
* 9 20
* / \
* 15 7
*
*
*
* return its zigzag level order traversal as:
*
* [
* [3],
* [20,9],
* [15,7]
* ]
*
*
*/
// @lc code=start
/**
* Definition for a binary tree node.
* function TreeNode(val, left, right) {
* this.val = (val===undefined ? 0 : val)
* this.left = (left===undefined ? null : left)
* this.right = (right===undefined ? null : right)
* }
*/
/**
* @param {TreeNode} root
* @return {number[][]}
*/
var zigzagLevelOrder = function (root) {
let result = [],
levelBuffer,
levelNum,
nodes = [],
direction = false;
nodes.push(root);
if (root !== null) result.push([root.val]);
while (nodes.length > 0) {
levelBuffer = [];
levelNum = [];
while (nodes.length > 0) {
let treeNode = nodes.shift();
if (treeNode !== null) {
levelBuffer.push(treeNode.left);
levelBuffer.push(treeNode.right);
}
}
nodes = nodes.concat(levelBuffer);
while (levelBuffer.length > 0) {
let treeNode = direction
? levelBuffer.shift()
: levelBuffer.pop();
if (treeNode !== null) {
levelNum.push(treeNode.val);
}
}
if (levelNum.length === 0) return result;
result.push(levelNum);
direction = !direction;
}
return result;
};
// @lc code=end
// [1,2,3,4,null,null,5]
// [1,2,3,4,null,null,5,6,7,null,8,9,10]
// [1,2,3,4,null,null,5,6,7,null,null,null,null,8,9]