How to skip the failed property automatically whitout exception when deserializing?

[emako]

Feel free to ask any question on how to use the library. Alternatively, consider asking the question on Stackoverflow, tagged with yamldotnet.

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Is there any scheme to automatically skip the property of the exception when deserializing?

Such as:

config.yaml:

first: something1 
second: something2 
third: something3

Config.cs:

public class Config
{
    public string first { get; set; }
    public string second { get; set; }
}

Because third is not in the class, deserialization will fail and an exception will be thrown.

How can it skip the third property automatically and continute the deserialization whitout exception.

The purpose is to construct Config class entities as much as possible.

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I know YamlDotNet.Dynamic or RepresentationModel can do it, but it's manual, not automatic.

[EdwardCooke]

On the DeserializerBuilder call IgnoreUnmatchedProperties. That worked when I just tested it.

var deserializer = new DeserializerBuilder().IgnoreUnmatchedProperties().Build();
var yaml = @"
first: something1 
second: something2 
third: something3
";

var config = deserializer.Deserialize<Config>(yaml);
class Config
{
    public string first { get; set; }
    public string second { get; set; }
}

[EdwardCooke]

Re open if you need further help.