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liniked_list_sort_list.cpp
75 lines (66 loc) · 1.86 KB
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liniked_list_sort_list.cpp
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/*
Given the head of a linked list, return the list after sorting it in ascending order.
Input: head = [4,2,1,3]
Output: [1,2,3,4]
Input: head = [-1,5,3,4,0]
Output: [-1,0,3,4,5]
Input: head = []
Output: []
Constraints:
The number of nodes in the list is in the range [0, 5 * 104].
-105 <= Node.val <= 105
Follow up: Can you sort the linked list in O(n logn) time and O(1) memory (i.e. constant space)?
*/
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode() : val(0), next(nullptr) {}
* ListNode(int x) : val(x), next(nullptr) {}
* ListNode(int x, ListNode *next) : val(x), next(next) {}
* };
*/
class Solution {
public:
ListNode* compute_midpoint(ListNode* head){
if(head == NULL || head->next == NULL){
return head;
}
ListNode* slow = head;
ListNode* fast = head->next;
while(fast != NULL && fast->next != NULL){
slow = slow->next;
fast = fast->next->next;
}
return slow;
}
ListNode* merge_two_lists(ListNode* A, ListNode* B){
if(A == NULL)
return B;
else if(B == NULL)
return A;
ListNode* C = NULL;
if(A->val < B->val){
C = A;
C->next = merge_two_lists(A->next, B);
}
else{
C = B;
C->next = merge_two_lists(A, B->next);
}
return C;
}
ListNode* sortList(ListNode* head) {
if(head == NULL || head->next == NULL)
return head;
ListNode* mid = compute_midpoint(head);
ListNode* A = head;
ListNode* B = mid->next;
mid->next = NULL;
A = sortList(A);
B = sortList(B);
ListNode* C = merge_two_lists(A, B);
return C;
}
};