Saving all images individually generated into a new directory

[ghost]

So i understand from #38
how to save 64 augmented images of one input by the response given and if I don't include the first line as in:

images = [image] * 64 #do not include this line
images_aug = seq.augment_images(images)
for i, image_aug in enumerate(images_aug):
misc.imsave("/home/user/new_folder/image_%06d.jpg" % (i,), image_aug)

I will only get one single image of all the ones li have in the array "images".

However say I have 8 images as input and I specified rows = 8 and cols = 8 so it should create 64 different versions of each input images, so now I should be able to get 512 new images. I would like to know how I can save all those 512 images into a new directory.

[aleju]

Assuming you have already a method to load your images to augment as images and an augmentation sequence as seq, then you could do the following to generate and save 64 augmented versions per image (and save them to /tmp/images_aug/<image_number>_<augmentation_number>.jpg).

import os
from scipy import misc

images = ...
seq = ...

write_to_dir = "/tmp/images_aug"
n_augs_per_image = 8 * 8

for i, image in enumerate(images):
    image_augs = seq.augment_images([image] * n_augs_per_image)
    for j, image_aug in enumerate(image_augs):
        misc.imsave(os.path.join(write_to_dir, "%06d_%02d.jpg" % (i, j)), image_aug)

misc.imsave is deprecated, but currently still useable.