/
circle.py
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circle.py
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# -------------
# User Instructions
#
# Now you will be incorporating fixed points into
# your smoother.
#
# You will need to use the equations from gradient
# descent AND the new equations presented in the
# previous lecture to implement smoothing with
# fixed points.
#
# Your function should return the newpath that it
# calculates.
#
# Feel free to use the provided solution_check function
# to test your code. You can find it at the bottom.
#
# --------------
# Testing Instructions
#
# To test your code, call the solution_check function with
# two arguments. The first argument should be the result of your
# smooth function. The second should be the corresponding answer.
# For example, calling
#
# solution_check(smooth(testpath1), answer1)
#
# should return True if your answer is correct and False if
# it is not.
from math import *
# Do not modify path inside your function.
path=[[0, 0], #fix
[1, 0],
[2, 0],
[3, 0],
[4, 0],
[5, 0],
[6, 0], #fix
[6, 1],
[6, 2],
[6, 3], #fix
[5, 3],
[4, 3],
[3, 3],
[2, 3],
[1, 3],
[0, 3], #fix
[0, 2],
[0, 1]]
# Do not modify fix inside your function
fix = [1, 0, 0, 0, 0, 0, 1, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 0]
######################## ENTER CODE BELOW HERE #########################
def smooth(path, fix, weight_data = 0.0, weight_smooth = 0.1, tolerance = 0.00001):
#
# Enter code here.
# The weight for each of the two new equations should be 0.5 * weight_smooth
#
newpath = [[0 for col in range(len(path[0]))] for row in range(len(path))]
for i in range(len(path)):
for j in range(len(path[0])):
newpath[i][j] = path[i][j]
change = tolerance
while (change >= tolerance):
change = 0.0
for i in range(len(path)):
if not fix[i]:
for j in range(len(path[0])):
aux = newpath[i][j]
newpath[i][j] = newpath[i][j] + weight_data * (path[i][j] - newpath[i][j])
last = newpath[(i-1) % len(newpath)][j]
nextone = newpath[(i+1) % len(newpath)][j]
newpath[i][j] = newpath[i][j] + weight_smooth * (last + nextone - (2.0 * newpath[i][j]))
#new equation
last2 = newpath[(i-2) % len(newpath)][j]
next2 = newpath[(i+2) % len(newpath)][j]
weight = 0.5 * weight_smooth
steplast = 2*last-last2-newpath[i][j]
newpath[i][j] = newpath[i][j]+weight*steplast
stepnext = 2*nextone-next2-newpath[i][j]
newpath[i][j] = newpath[i][j]+weight*stepnext
change += abs(aux - newpath[i][j])
return newpath
#thank you - EnTerr - for posting this on our discussion forum
##newpath = smooth(path)
##for i in range(len(path)):
## print '['+ ', '.join('%.3f'%x for x in path[i]) +'] -> ['+ ', '.join('%.3f'%x for x in newpath[i]) +']'
# --------------------------------------------------
# check if two numbers are 'close enough,'used in
# solution_check function.
#
def close_enough(user_answer, true_answer, epsilon = 0.03):
if abs(user_answer - true_answer) > epsilon:
return False
return True
# --------------------------------------------------
# check your solution against our reference solution for
# a variety of test cases (given below)
#
def solution_check(newpath, answer):
if type(newpath) != type(answer):
print "Error. You do not return a list."
return False
if len(newpath) != len(answer):
print 'Error. Your newpath is not the correct length.'
return False
if len(newpath[0]) != len(answer[0]):
print 'Error. Your entries do not contain an (x, y) coordinate pair.'
return False
for i in range(len(newpath)):
for j in range(len(newpath[0])):
if not close_enough(newpath[i][j], answer[i][j]):
print 'Error, at least one of your entries is not correct.'
return False
print "Test case correct!"
return True
# --------------
# Testing Instructions
#
# To test your code, call the solution_check function with
# two arguments. The first argument should be the result of your
# smooth function. The second should be the corresponding answer.
# For example, calling
#
# solution_check(smooth(testpath1), answer1)
#
# should return True if your answer is correct and False if
# it is not.
testpath1=[[0, 0], #fix
[1, 0],
[2, 0],
[3, 0],
[4, 0],
[5, 0],
[6, 0], #fix
[6, 1],
[6, 2],
[6, 3], #fix
[5, 3],
[4, 3],
[3, 3],
[2, 3],
[1, 3],
[0, 3], #fix
[0, 2],
[0, 1]]
testfix1 = [1, 0, 0, 0, 0, 0, 1, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 0]
answer1 = [[0, 0],
[0.7938620981547201, -0.8311168821106101],
[1.8579052986461084, -1.3834788165869276],
[3.053905318597796, -1.5745863173084],
[4.23141390533387, -1.3784271816058231],
[5.250184859723701, -0.8264215958231558],
[6, 0],
[6.415150091996651, 0.9836951698796843],
[6.41942442687092, 2.019512290770163],
[6, 3],
[5.206131365604606, 3.831104483245191],
[4.142082497497067, 4.383455704596517],
[2.9460804122779813, 4.5745592975708105],
[1.768574219397359, 4.378404668718541],
[0.7498089205417316, 3.826409771585794],
[0, 3],
[-0.4151464728194156, 2.016311854977891],
[-0.4194207879552198, 0.9804948340550833]]
testpath2 = [[0, 0], # fix
[2, 0],
[4, 0], # fix
[4, 2],
[4, 4], # fix
[2, 4],
[0, 4], # fix
[0, 2]]
testfix2 = [1, 0, 1, 0, 1, 0, 1, 0]
answer2 = [[0, 0],
[2.0116767115496095, -0.7015439080661671],
[4, 0],
[4.701543905420104, 2.0116768147460418],
[4, 4],
[1.9883231877640861, 4.701543807525115],
[0, 4],
[-0.7015438099112995, 1.9883232808252207]]
solution_check(smooth(testpath1, testfix1), answer1)
solution_check(smooth(testpath2, testfix2), answer2)
for i in range(len(testpath1)):
print '['+ ', '.join('%.3f'%x for x in answer1[i]) +'] -> ['+ ', '.join('%.3f'%x for x in smooth(testpath1, testfix1)[i]) +']'
for i in range(len(testpath2)):
print '['+ ', '.join('%.3f'%x for x in answer2[i]) +'] -> ['+ ', '.join('%.3f'%x for x in smooth(testpath2, testfix2)[i]) +']'