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请问一下,dexposedbridge.jar里面的源码怎么获取,我想在产品上写一些service类,然后把所有的jar包合并成一个,通过AndroidStudio自动解析得到的.class文件中,在xposedbridge.class中有
public static Unhook hookMethod(Member hookMethod, XC_MethodHook callback) {
.......
DexposedBridge.AdditionalHookInfo additionalInfo = new DexposedBridge.AdditionalHookInfo(callbacks, parameterTypes, returnType, (DexposedBridge.AdditionalHookInfo)null);
.........................
return new Unhook(callback, hookMethod);
}
其中(DexposedBridge.AdditionalHookInfo)null)这种写法是什么意思,还有 new Unhook(callback, hookMethod);其中Unhook的构造函数只有hookMethod一个参数啊,这怎么可以传递两个参数呢?
public class Unhook implements IXUnhook {
private final Member hookMethod;
public Unhook(Member hookMethod) {
this.hookMethod = hookMethod;
}
请问一下,dexposedbridge.jar里面的源码怎么获取,我想在产品上写一些service类,然后把所有的jar包合并成一个,通过AndroidStudio自动解析得到的.class文件中,在xposedbridge.class中有
public static Unhook hookMethod(Member hookMethod, XC_MethodHook callback) {
.......
DexposedBridge.AdditionalHookInfo additionalInfo = new DexposedBridge.AdditionalHookInfo(callbacks, parameterTypes, returnType, (DexposedBridge.AdditionalHookInfo)null);
.........................
return new Unhook(callback, hookMethod);
}
其中(DexposedBridge.AdditionalHookInfo)null)这种写法是什么意思,还有 new Unhook(callback, hookMethod);其中Unhook的构造函数只有hookMethod一个参数啊,这怎么可以传递两个参数呢?
public class Unhook implements IXUnhook {
private final Member hookMethod;
.....................
}
我不确定这种写法是什么意思,是反编译的问题吗?不知道可以不可以提供dexposebridge.jar里面的源码?我现在是自己反编译后,想和其他的代码一起打包,一直报错,求帮助,我水平比较有限,但是很感兴趣,谢谢
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