请问能获取到CPU分别在 1min, 5min, 15min内的CPU使用情况吗?

[zhihuitang]

No description provided.

[aozhimin]

@zhihuitang 没太清楚这个问题的意思，起一个子线程每隔一秒钟就抓一次 CPU 使用情况，这样再看 1min, 5min, 15min内的CPU使用情况，能满足你这个需求吗？

[zhihuitang]

@aozhimin 谢谢,在Swift中已经找到方法了, 就是获得uptime后面的CPU占用率(1min, 5min, 15min)

func getCPULoadAvg() -> [Double]{
        var loadAvg = [Double](repeating: 0, count: 3)
        getloadavg(&loadAvg, 3)
        return loadAvg
    }

[zhihuitang]

在Objective-C中是这样的:

typedef struct {
    double m1;
    double m5;
    double m15;
} Upclodavg;


+ (Upclodavg)lodavg {
    double loadavg[3];
    getloadavg(loadavg, 3);
    Upclodavg cpuLoadAvg = {0,0,0};
    
    // 1 mins
    cpuLoadAvg.m1 = loadavg[0];
    
    // 5 mins
    cpuLoadAvg.m5 = loadavg[1];
    
    // 15 mins
    cpuLoadAvg.m15 = loadavg[2];
    return cpuLoadAvg;
}

[aozhimin]

@zhihuitang 好的，明白了，
Libc 的 getloadavg

/*
 * getloadavg() -- Get system load averages.
 *
 * Put `nelem' samples into `loadavg' array.
 * Return number of samples retrieved, or -1 on error.
 */
int
getloadavg(loadavg, nelem)
	double loadavg[];
	int nelem;
{
	struct loadavg loadinfo;
	int i, mib[2];
	size_t size;

	mib[0] = CTL_VM;
	mib[1] = VM_LOADAVG;
	size = sizeof(loadinfo);
	if (sysctl(mib, 2, &loadinfo, &size, NULL, 0) < 0)
		return (-1);

	nelem = MIN(nelem, sizeof(loadinfo.ldavg) / sizeof(fixpt_t));
	for (i = 0; i < nelem; i++)
		loadavg[i] = (double) loadinfo.ldavg[i] / loadinfo.fscale;
	return (nelem);
}