Fragment doesn't get code generated when embedded in inline fragment with same type information

[fruitcoder]

In the following example:

query Details($id: ID!) {
  viewer {
    Model(id: $clipId) {
      id
      ...BasicInfo
      recommendations {
        edges {
          node {
            id
            ... on ModelInterface {
              ...BasicInfo
            }
          }
        }
      }
    }
  }
}

fragment BasicInfo on ModelInterface {
  title
}

we get the following code generation:

public struct Recommendation: GraphQLMappable {
  public let __typename = "XXXConnection"
  public let edges: [Edge?]?

  public init(reader: GraphQLResultReader) throws {
    edges = try reader.optionalList(for: Field(responseName: "edges"))
  }

  public struct Edge: GraphQLMappable {
    public let __typename = "XXXEdge"
    public let node: Node?

    public init(reader: GraphQLResultReader) throws {
      node = try reader.optionalValue(for: Field(responseName: "node"))
    }

    public struct Node: GraphQLMappable {
      public let __typename: String
      public let id: GraphQLID

      public init(reader: GraphQLResultReader) throws {
        __typename = try reader.value(for: Field(responseName: "__typename"))
        id = try reader.value(for: Field(responseName: "id"))
      }
    }
  }
}

The type constraint for the conditional fragment to be a ModelInterface is redundant but the fragment should still be included in the generated code.

[martijnwalraven]

I believe this has been fixed in Apollo iOS 0.6.0-beta.1. Make sure to use npm install -g apollo-codegen@next until it is out of beta.