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馃悰 Bug Report: Param "userId" is not optional #33

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jofftiquez opened this issue Mar 9, 2022 · 7 comments
Closed
2 tasks done

馃悰 Bug Report: Param "userId" is not optional #33

jofftiquez opened this issue Mar 9, 2022 · 7 comments
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@jofftiquez
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馃憻 Reproduction steps

Just create a new account in Signup

馃憤 Expected behavior

Signing up should go through with new credentials

馃憥 Actual Behavior

Getting error:

image

馃幉 Appwrite version

Different version (specify in environment)

馃捇 Operating system

Linux

馃П Your Environment

This is the demo app

馃憖 Have you spent some time to check if this issue has been raised before?

  • I checked and didn't find similar issue

馃彚 Have you read the Code of Conduct?

@jofftiquez jofftiquez added the bug Something isn't working label Mar 9, 2022
@vic-developer
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vic-developer commented Mar 23, 2022

I'm getting cors issues on localhost, not sure if that's related.
or
URL constructor: localhost/api/v1/account is not a valid URL.
Any clues how to resolve?

@jofftiquez
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I'm getting cors issues on localhost, not sure if that's related. or URL constructor: localhost/api/v1/account is not a valid URL. Any clues how to resolve?

Haven't retested again myself yet.

@rumbis
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rumbis commented Sep 28, 2022

i got the same issue

@stnguyen90
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@jofftiquez, is this still a problem? It looks like the code has been updated to pass a userId:

return api.provider().account.create('unique()', email, password, name);

@stnguyen90 stnguyen90 self-assigned this Apr 21, 2023
@jofftiquez
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@jofftiquez, is this still a problem? It looks like the code has been updated to pass a userId:

return api.provider().account.create('unique()', email, password, name);

Hello, sorry but I haven't tested it myself again.

@stnguyen90 stnguyen90 changed the title 馃悰 Bug Report: 馃悰 Bug Report: Param "userId" is not optional Apr 25, 2023
@stnguyen90
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@jofftiquez is it okay if I close this and you can open a new issue if you're still running into this problem?

@jofftiquez
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Sure thing! @stnguyen90

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