How to trigger interceptors request error ？

[ch-zgh-1993]

which config for request, can tirgger interceptors request error ?

thanks for your answer!

[yasuf]

That request interceptor error will be triggered when there's an error with the interceptor, you can test this by doing:

    axios.interceptors.request.use(
      () => {
        throw new Error("My error");
      },
      () => {
        debugger;
      }
    );
    axios
      .get("https://jsonplaceholder.typicode.com/users")
      .then(res => {
        const persons = res.data;
        this.setState({ persons });
      });

You get to the debugger because there's an error triggered in the interceptor

[ch-zgh-1993]

The error is not catched and not run debugger... But when register debugger interceptor.request first, and then register other interceptor.request to throw new Error, the debugger is triggered. Can you tell me why? what wrong things with i trying?

axios.interceptors.request.use(
  () => {
    // throw new Error('My error')
  },
  () => {
  	debugger
  }
)
axios.interceptors.request.use(function (config) {
    // Do something before request is sent
    throw new Error('My error')
    return config;
  }, function (error) {
    // Do something with request error
    return Promise.reject(error);
  });

thanks for your answer!

[chinesedfan]

@ch-zgh-1993 What you need is some practices about promises. Good luck!

axios.interceptors.request.use(f1, f2)
axios.interceptors.request.use(f3, f4)

// is much similar with
promise.then(f1, f2).then(f3, f4)

If you are familiar with Promises, you will know that f2 can't catch errors in f1, but f4 can.
And f4 can't catch errors in f3.

[ch-zgh-1993]

I know this. but its right design about catch request.use error? if only one reques.use, what effect about debugger ?

// Add a request interceptor
axios.interceptors.request.use(function (config) {
    // Do something before request is sent
    return config;
  }, function (error) {
     debugger
    // Do something with request error
    return Promise.reject(error);
  });

[chinesedfan]

See #1556. Someone has the same curiosity with you.