do-expressions and nested breaks

[bakkot]

Bug Report

console.log(
  do {
    switch ("1") {
      case "1":
        if (true) {
          "out";
          break;
        }
    }
  }
);

console.log(
  do {
    x: {
      "out";
      break x;
    }
  }
);

This should print "out" twice. Instead it prints undefined twice.

• REPL

[babel-bot]

Hey @bakkot! We really appreciate you taking the time to report an issue. The collaborators on this project attempt to help as many people as possible, but we're a limited number of volunteers, so it's possible this won't be addressed swiftly.

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[barronwei]

Could I work on this?

[nicolo-ribaudo]

Sure! If you need any help, feel free to ask here or on slack.

[barronwei]

Looks like the conditional is causing the bug in the first case. Just to clarify, should the first case print "out" instead of 1, @bakkot?

[bakkot]

@barronwei Yes, sorry. Edited the original post to fix it.