delete-node-in-a-linked-list.py

# -*- coding:utf-8 -*-


# Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.
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# Given linked list -- head = [4,5,1,9], which looks like following:
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# Example 1:
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# Input: head = [4,5,1,9], node = 5
# Output: [4,1,9]
# Explanation: You are given the second node with value 5, the linked list should become 4 -> 1 -> 9 after calling your function.
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# Example 2:
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# Input: head = [4,5,1,9], node = 1
# Output: [4,5,9]
# Explanation: You are given the third node with value 1, the linked list should become 4 -> 5 -> 9 after calling your function.
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# Note:
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# 	The linked list will have at least two elements.
# 	All of the nodes' values will be unique.
# 	The given node will not be the tail and it will always be a valid node of the linked list.
# 	Do not return anything from your function.
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# Definition for singly-linked list.
# class ListNode(object):
#     def __init__(self, x):
#         self.val = x
#         self.next = None

class Solution(object):
    def deleteNode(self, node):
        """
        :type node: ListNode
        :rtype: void Do not return anything, modify node in-place instead.
        """
        node.val = node.next.val
        node.next = node.next.next