How to Pass path argument(key) to Lambda using Boto3 and Invoke my Flask APP deployed as AWS Lambda ?

[SamvelChan]

I have flask add deployed as Lambda Function through Zappa. I want call lambda function exposing the end point /v1/key using boto3 and pass path argument(key). Can you please help me with it ?

Flask APP code
`
def create_app():

""" Create Flask application. """
app = Flask('myapp')
app.api = Api(app)
app.api.add_resource(Info, '/v1/path:key')
app.api.add_resource(Health, '/health')
return app

app=create_app()

@app.route('/')
def hello_world():
return jsonify({"message": "Hello World!"})

if name == 'main':
app.run()

class Info(SignatureSecuredResource):

def get(self, key):
log.info('key = %s' % key)

`

Boto3 invocation

`
import boto3
import json

if name == 'main':
# create lambda client
client = boto3.client('lambda',
region_name= 'us-east-1',
aws_access_key_id='',
aws_secret_access_key='')
payload = {'key': 'test'}
payload = json.dumps(payload)
result = client.invoke(FunctionName='lambda-func',InvocationType='RequestResponse',
LogType='Tail',Payload=payload)
range = result['Payload'].read()
data = json.loads(range)
print(data)
`

[SamvelChan]

https://stackoverflow.com/questions/59273890/invoke-api-end-points-with-in-lambda-using-boto-and-pass-arguments

[swetashre]

@SamvelChan - Thank you for your post. Your application needs to send it as part of the payload.
Basically the django app needs to provide in the payload any data your function needs. When you invoke lambda it will call your function handler. Your handler should process the payload as needed.

I found this post which explains this process step by step with code sample:
https://qxf2.com/blog/invoking-aws-lambda-functions-from-a-flask-app/

Hope it helps.

[no-response]

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