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solve_NQueens_Sudoku.py
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solve_NQueens_Sudoku.py
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#!/usr/bin/python
# coding=utf-8
'''
__author__ = 'sunp'
__date__ = '2018/12/20'
'''
# 51. N-Queens
# 52. N-Queens II
'''
This is a classic backtracking problem.
How to translate the problem into programming model?
1. Start row by row, and loop through columns;
2. Check if any queen exists in preceding directions;
3. Find {solutions} or its count.
'''
class Solution1(object):
def solveNQueens(self, n):
"""
:type n: int
:rtype: List[List[str]]
"""
# find all solutions
self.res = []
self.board = [['.'] * n for _ in range(n)]
self.dfs(0, n)
return self.res
def dfs(self, row, n):
if row == n:
self.res.append([''.join(line) for line in self.board])
return
for col in range(n):
if self.is_valid(row, col, n):
self.board[row][col] = 'Q'
self.dfs(row + 1, n)
self.board[row][col] = '.'
def is_valid(self, row, col, n):
# upper vertical
for i in range(row):
if self.board[i][col] == 'Q':
return False
# left upper diagonal
for i, j in zip(range(row - 1, -1, -1), range(col - 1, -1, -1)):
if self.board[i][j] == 'Q':
return False
# right upper diagonal
for i, j in zip(range(row - 1, -1, -1), range(col + 1, n)):
if self.board[i][j] == 'Q':
return False
return True
# 37. Sudoku Solver
'''
1. Find empty location one by one, if none then solved;
2. Check if same digit exists in violation of rules;
3. Regain current value if not solved.
'''
class Solution2(object):
def solveSudoku(self, board):
"""
:type board: List[List[str]]
:rtype: void Do not return anything, modify board in-place instead.
"""
# find one solution
self.board = board
self.dfs()
def dfs(self):
loc = [-1, -1]
if not self.find_empty_loc(loc):
return True
row, col = tuple(loc)
for num in range(1, 10):
if self.is_valid(row, col, str(num)):
self.board[row][col] = str(num)
if self.dfs():
return True
else:
self.board[row][col] = '.'
return False
def find_empty_loc(self, loc):
for i in range(9):
for j in range(9):
if self.board[i][j] == '.':
loc[0] = i
loc[1] = j
return True
return False
def is_valid(self, row, col, digit):
# used in row
for i in range(9):
if self.board[row][i] == digit:
return False
# used in col
for j in range(9):
if self.board[j][col] == digit:
return False
# used in sub-box
row, col = row - row % 3, col - col % 3
for i in range(3):
for j in range(3):
if self.board[row + i][col + j] == digit:
return False
return True