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If var is a nodejs require, don't check the name
Fixes #31
var fs = require("fs")
In the above case, it's fine that variable is named fs because
this is a pattern in nodejs (and other common module implementations)
The parser will check that A/ it's a require function call, and
B/ that the name of the module corresponds to the name of the var
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Patrick Brosset
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Feb 9, 2012
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var fs = require("fs"); |