Average Precision Computation

[kemaloksuz]

Hi,

I noticed that while in the paper in Equation 5 during AP derivation, you add 1 both to the nominator and to the denominator following simply the formulation of AP.

But in this line of the code, you add 0.5 to the variable a and then estimate the precision by a/(a+b), which implies 0.5 is added to nominator and denominator. I understand all of your code and match with the paper, but I only could not see why you add 0.5 instead of 1 here. Am I missing something?

Thanks for your time

Kemal

[cccorn]

In this code, the variable tmp1 contains f(x_{ii}) (f is the piecewise step function, i is the positive index), while in the Eq 5 of the paper, the summation is taken with j \neq i.
So the summation of tmp1 already has a 0.5=f(x_{ii}), just need to add another 0.5 to obtain 1.

[kemaloksuz]

OK, I see now. Thank you for the quick replies.

[www516717402]

great help.