Why divide by 32768?

[aunyks]

On lines 108 and 109 in main.rs, why do we divide the f32s by 32768? What does this action achieve?

When reading these lines, it appeared to me that the bitwise operations successfully converted the u8 values into f32 values, but I don't quite understand why they're divided by a number afterward.

let i: f32 = ((b[1] as i16) << 8 | b[0] as i16) as f32 / 32768.;
let q: f32 = ((b[3] as i16) << 8 | b[2] as i16) as f32 / 32768.;

[andresv]

i and q are normalized to -1.0..1.0