Skip to content

Latest commit

 

History

History
253 lines (173 loc) · 4.67 KB

Day_21.md

File metadata and controls

253 lines (173 loc) · 4.67 KB
Raw

Question 85

Question

By using list comprehension, please write a program to print the list after removing the 0th,4th,5th numbers in [12,24,35,70,88,120,155].

Hints

Use list comprehension to delete a bunch of element from a list.Use enumerate() to get (index, value) tuple.

Main author's Solution: Python 2

li = [12,24,35,70,88,120,155]
li = [x for (i,x) in enumerate(li) if i not in (0,4,5)]
print li

My Solution: Python 3

li = [12,24,35,70,88,120,155]
li = [li[i] for i in range(len(li)) if i not in (0,4,5)]
print(li)
'''Solution by: pratikb0501
'''
li = [12, 24, 35, 70, 88, 120, 155]
print(list(j for i, j in enumerate(li) if i != 0 and i != 4 and i != 5))

Question 86

Question

By using list comprehension, please write a program to print the list after removing the value 24 in [12,24,35,24,88,120,155].

Hints

Use list's remove method to delete a value.

Main author's Solution: Python 2

li = [12,24,35,24,88,120,155]
li = [x for x in li if x!=24]
print li

My Solution: Python 3

li = [12,24,35,24,88,120,155]
li.remove(24)  # this will remove only the first occurrence of 24
print(li)

Question 87

Question

With two given lists [1,3,6,78,35,55] and [12,24,35,24,88,120,155], write a program to make a list whose elements are intersection of the above given lists.

Hints

Use set() and "&=" to do set intersection operation.

Main author's Solution: Python 2

set1=set([1,3,6,78,35,55])
set2=set([12,24,35,24,88,120,155])
set1 &= set2
li=list(set1)
print li

My Solution: Python 3

list1 = [1,3,6,78,35,55]
list2 = [12,24,35,24,88,120,155]
set1= set(list1)
set2= set(list2)
intersection = set1 & set2
print(intersection)

OR

list1 = [1,3,6,78,35,55]
list2 = [12,24,35,24,88,120,155]
set1= set(list1)
set2= set(list2)
intersection = set.intersection(set1,set2)
print(intersection)

Question 88

Question

With a given list [12,24,35,24,88,120,155,88,120,155], write a program to print this list after removing all duplicate values with original order reserved.

Hints

Use set() to store a number of values without duplicate.

Main author's Solution: Python 2

def removeDuplicate( li ):
    newli=[]
    seen = set()
    for item in li:
        if item not in seen:
            seen.add( item )
            newli.append(item)

    return newli

li=[12,24,35,24,88,120,155,88,120,155]
print removeDuplicate(li)

My Solution: Python 3

li = [12,24,35,24,88,120,155,88,120,155]
for i in li:
    if li.count(i) > 1:
        li.remove(i)
print(li)

OR

def removeDuplicate( li ):
    seen = {}  # dictionary
    for item in li:
        if item not in seen:
            seen[item] = True
            yield item

li = [12, 24, 35, 24, 88, 120, 155, 88, 120, 155]
ans = list(removeDuplicate(li))
print(ans)

Question 89

Question

Define a class Person and its two child classes: Male and Female. All classes have a method "getGender" which can print "Male" for Male class and "Female" for Female class.

Hints

Use Subclass(Parentclass) to define a child class.

Solution:

class Person(object):
    def getGender( self ):
        return "Unknown"

class Male( Person ):
    def getGender( self ):
        return "Male"

class Female( Person ):
    def getGender( self ):
        return "Female"

aMale = Male()
aFemale= Female()
print aMale.getGender()
print aFemale.getGender()
'''Solution by: popomaticbubble
'''
class Person(object):
    def __init__(self):
	self.gender = "unknown"

    def getGender(self):
	print(self.gender)

class Male(Person):
    def __init__(self):
	self.gender = "Male"

class Female(Person):
    def __init__(self):
	self.gender = "Female"

sharon = Female()
doug = Male()
sharon.getGender()
doug.getGender()

go to previous day

go to next day

Discussion