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Question 100

Question

You are given words. Some words may repeat. For each word, output its number of occurrences. The output order should correspond with the input order of appearance of the word. See the sample input/output for clarification.

If the following string is given as input to the program:

4
bcdef
abcdefg
bcde
bcdef

Then, the output of the program should be:

3
2 1 1

Hints

Make a list to get the input order and a dictionary to count the word frequency

My Solution: Python 3

n = int(input())

word_list = []
word_dict = {}

for i in range(n):
    word = input()
    if word not in word_dict:
        word_list.append(word)
    word_dict[word] = word_dict.get(word, 0) + 1

print(len(word_list))
for word in word_list:
    print(word_dict[word], end=' ')

Question 101

Question

You are given a string.Your task is to count the frequency of letters of the string and print the letters in descending order of frequency.

If the following string is given as input to the program:

aabbbccde

Then, the output of the program should be:

b 3
a 2
c 2
d 1
e 1

Hints

Count frequency with dictionary and sort by Value from dictionary Items

My Solution: Python 3

word = input()
dct = {}
for i in word:
    dct[i] = dct.get(i,0) + 1

dct = sorted(dct.items(),key=lambda x: (-x[1],x[0]))
for i in dct:
    print(i[0],i[1])
'''Solution by: yuan1z'''

X = input()
my_set = set(X)
arr = []
for item in my_set:
    arr.append([item,X.count(item)])
tmp = sorted(arr,key = lambda x: (-x[1],x[0]))

for i in tmp:
    print(i[0]+' '+str(i[1]))
'''Solution by: StartZer0'''

s = list(input())

dict_count_ = {k:s.count(k) for k in s}
list_of_tuples = [(k,v) for k,v in dict_count_.items()]
list_of_tuples.sort(key = lambda x: x[1], reverse = True)

for item in list_of_tuples:
  print(item[0], item[1])

Question 102

Question

Write a Python program that accepts a string and calculate the number of digits and letters.

Input

Hello321Bye360

Output

Digit - 6
Letter - 8

Hints

Use isdigit() and isalpha() function

Solution:

word = input()
digit,letter = 0,0
for char in word:
    digit+=char.isdigit()
    letter+=char.isalpha()

print('Digit -',digit)
print('Letter -',letter)

Question 103

Question

Given a number N.Find Sum of 1 to N Using Recursion

Input

5

Output

15

Hints

Make a recursive function to get the sum

Solution:

def rec(n):
    if n == 0:
        return n
    return rec(n-1) + n


n = int(input())
sum = rec(n)
print(sum)
"""Solution by: popomaticbubble
"""
def summer(counter, n, current):
    if n == 0:
        return 0
    if counter == n:
        return current+n
    else:
        current = current + counter
        counter += 1
        return summer(counter, n, current)


N = int(input("> "))
print(summer(1, N, 0))

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