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第五章 式(5.2) 中最后推导梯度的时候,\hat(yi)也应该是关于w的函数,没有对其求导,直接当成常数处理了,这似乎是不正确的。 #128

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wanyixue opened this issue Mar 18, 2023 · 1 comment

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@wanyixue
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\hat(yi)应该是阶越函数的输出,而阶越函数不可导,也没有subgradient,30页直接将\hat(yi)写入了求导的结果,似乎是不正确的。

@wanyixue wanyixue changed the title 第五章 式(5.2) 中最后推导梯度的时候,\hat(yi)也应该是关于w的函数,没有对齐求导,直接当成常数处理了,这似乎是不正确的。 第五章 式(5.2) 中最后推导梯度的时候,\hat(yi)也应该是关于w的函数,没有对其求导,直接当成常数处理了,这似乎是不正确的。 Mar 18, 2023
@wanyixue wanyixue reopened this Mar 18, 2023
@Sm1les
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Sm1les commented Mar 18, 2023

已在#64 (comment) 答复

@Sm1les Sm1les closed this as completed Mar 18, 2023
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