If you have an incredibly large log file.. kerneloops takes too long.

Just parse the last 32Mb instead, should be plenty.

dmesg.c

@@ -40,6 +40,8 @@ static char **linepointer;
 static char *linelevel;
 static int linecount;
 
+#define MAX(A,B) ((A) > (B) ? (A) : (B))
+
 
 /*
  * This function splits the dmesg buffer data into lines
@@ -352,6 +354,7 @@ void scan_filename(char *filename, int issyslog)
 	struct stat statb;
 	FILE *file;
 	int ret;
+	size_t buflen;
 
 	memset(&statb, 0, sizeof(statb));
 
@@ -364,21 +367,28 @@ void scan_filename(char *filename, int issyslog)
 	 * in theory there's a race here, since someone could spew
 	 * to /var/log/messages before we read it in... we try to
 	 * deal with it by reading at most 1023 bytes extra. If there's
-	 * more than that.. any oops will be in dmesg anyway
+	 * more than that.. any oops will be in dmesg anyway.
+	 * Do not try to allocate an absurt amount of memory; ignore
+	 * older log messages because they are unlikely to have
+	 * sufficiently recent data to be useful.  32MB is more
+	 * than enough; it's not worth looping through more log
+	 * if the log is larger than that.
 	 */
-	buffer = calloc(statb.st_size+1024, 1);
+	buflen = MAX(statb.st_size+1024, 32*1024*1024);
+	buffer = calloc(buflen, 1);
 	assert(buffer != NULL);
 
 	file = fopen(filename, "rm");
 	if (!file) {
 		free(buffer);
 		return;
 	}
-	ret = fread(buffer, 1, statb.st_size+1023, file);
+	fseek(file, -buflen, SEEK_END);
+	ret = fread(buffer, 1, buflen-1, file);
 	fclose(file);
 
 	if (ret > 0)
-		extract_oops(buffer, statb.st_size+1023, issyslog);
+		extract_oops(buffer, buflen-1, issyslog);
 	free(buffer);
 	if (opted_in >= 2)
 		submit_queue();