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fix: introduce dom.isHiddenWithCSS for use in dom.isFocusable #1211

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merged 9 commits into from
Nov 8, 2018

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jeeyyy
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@jeeyyy jeeyyy commented Oct 29, 2018

This PR does the below:

Closes issue:

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  • Follows the commit message policy, appropriate for next version
  • Has documentation updated, a DU ticket, or requires no documentation change
  • Includes new tests, or was unnecessary
  • Code is reviewed for security by: << Marcy Sutton >>

@jeeyyy jeeyyy requested a review from a team as a code owner October 29, 2018 12:25
* @param {HTMLElement} el The HTML Element
* @return {Boolean} the element's visibility status
*/
dom.isCssVisible = function isCssVisible(el) {
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I'm not sure about the name of this thing. It's not especially clear. How about we flip this around and call it dom.isHiddenWithCSS?


const style = window.getComputedStyle(el, null);
if (!style) {
return false;
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Should we just throw here instead, and have the check(s) catch it and resolve as incomplete? Seems more appropriate.

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I think this may be a bit intrusive to throw for this reason. Happy to discuss.

return false;
}

const parent = el.assignedSlot ? el.assignedSlot : el.parentNode;
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Should probably just use dom.getComposedParent

assert.isTrue(axe.commons.dom.isCssVisible(el));
});

it('should return true on detached elements', function() {
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"should return false"

assert.isTrue(axe.commons.dom.isCssVisible(el));
});

it('should return true and not calculate position on parents', function() {
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I don't know what the use of this test is.

assert.isFalse(axe.commons.dom.isCssVisible(el));
});

it('should correctly handle visible slotted elements', function() {
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We should toggle this test if shadow DOM is not available, instead of passing it without assertions.

'</div>';

var el = document.getElementById('target');
assert.isFalse(axe.commons.dom.isCssVisible(el));
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This should be true. Unlike display:none, which is a "once hidden, always hidden" kind of thing, you can make things visible inside of hidden regions.

@@ -0,0 +1,153 @@
describe('dom.isCssVisible', function() {
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This should have display:none tests that run even without shadow DOM. Also, the display:none test should check that if an ancestor is set to display:none, that changing display of its dependents doesn't show make them visible again (unlike with visibility).

@jeeyyy jeeyyy dismissed WilcoFiers’s stale review November 1, 2018 15:59

Updated. Review again.

@jeeyyy jeeyyy changed the title fix: introduce dom.isCssVisible function to be used in dom.isFocusable fix: introduce dom.isHiddenWithCSS for use in dom.isFocusable Nov 1, 2018
@jeeyyy jeeyyy requested a review from a team November 1, 2018 16:39
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jeeyyy commented Nov 1, 2018

@WilcoFiers - ready for review.


const style = window.getComputedStyle(el, null);
if (!style) {
throw new Error('Style does not exist for the given element.');
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Where would this scenario occur?

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I think this happens with unmounted elements.

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@marcysutton marcysutton Nov 8, 2018

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I don't even know how that would come up in the context of an audit, but ok :)

edit: maybe in a unit test where the context wasn't mounted? A lot of our other rules would have problems though.

* @param {Boolean} descendentVisibilityValue (Optional) immediate descendant visibility value used for recursive computation
* @return {Boolean} the element's hidden status
*/
dom.isHiddenWithCSS = function isHiddenWithCSS(el, descendentVisibilityValue) {
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I like the new name for this method. 👍

Are you pulling any of the code out of is-visible, or is that mostly duplicate at this point?

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This has some replication from is-visible and is-hidden. We may need to do some refactor afterwards.

assert.isFalse(actual);
});

it('should return false on detached elements', function() {
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When would this case arise? Would these even be returned from querying the DOM?

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You are right, probably won't be returned when querying the DOM. No harm in this test case, as that is exactly what we are testing.


const style = window.getComputedStyle(el, null);
if (!style) {
throw new Error('Style does not exist for the given element.');
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I think this happens with unmounted elements.

if (
(visibilityValue === 'hidden' && !descendentVisibilityValue) ||
(visibilityValue === 'hidden' &&
(descendentVisibilityValue && descendentVisibilityValue !== 'visible'))
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should be === 'hidden' There are more values on CSS visibility than just hidden and visible.


const parent = dom.getComposedParent(el);
if (parent) {
return dom.isHiddenWithCSS(parent, visibilityValue);
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Nice try on the recursion, but it doesn't work this way. This function shows #foo as hidden, which it isn't:

<div style="visibility:hidden">
  <div style="visibility:hidden">
    <div style="visibility:visible" id="foo">
      Visible
    </div>
  </div>
</div>

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Have tackled for the above.

@jeeyyy jeeyyy requested review from marcysutton, WilcoFiers and a team November 6, 2018 08:50
@jeeyyy jeeyyy changed the title fix: introduce dom.isHiddenWithCSS for use in dom.isFocusable [WIP] fix: introduce dom.isHiddenWithCSS for use in dom.isFocusable Nov 6, 2018
@jeeyyy jeeyyy changed the title [WIP] fix: introduce dom.isHiddenWithCSS for use in dom.isFocusable fix: introduce dom.isHiddenWithCSS for use in dom.isFocusable Nov 6, 2018
@jeeyyy jeeyyy merged commit 2cff417 into develop Nov 8, 2018
@jeeyyy jeeyyy deleted the is-css-visible branch November 8, 2018 09:33
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4 participants