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How to set SISO? #34
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There is a debugfs parameter called I can't find any scripts that use it, so I'm not sure exactly how it works any more – probably why this parameter is not documented in the FAQ. You will almost certainly want to set the parameter while the interface is disabled (e.g., before running You set it similarly to how you set other debugfs parameters including |
Thank you !I will try that.And it is really nice when you say IIRC.I think it sounds really cool!I will remember that abbreviation. :) |
Please let me know whether it works |
Hi Daniel,sorry for replying late.I tried it.I found the parameter 'rx_chains_msk' ,but I cannot configure it like monitor_tx_rate . Then,it shows that: I also used "1 antenna" & "2 antennas" to set it, but failed either. I want to set the parameter as you said,but I can't.Could you tell me some details about that?Thank you! |
I believe the argument is a number 0x1–0x7 corresponding to antenna A (0x1), B (0x2), C (0x4), or any combination of them by addition. So for example,
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Ok I will try it 5 hours later & I will tell you how it works.Thank you! In my opinion, the mask is fixed so I didn't try it yesterday. |
It worked well.I followed as you said,and figure it out.The SISO system has been done!Thank you very much!By the way,I want to ask you another question, as follow text shows: |
Dear Daniel, I also come up with an idea that if only one transmitter and multiple receivers in the system.Different receiver will get all the packets from the transmitter .What do you think this method could solve my problem which I mention in the last responding?Thank you! |
That For other questions, please start new issues – it sounds like you got receive antenna selection to work, so I'm closing this one! |
You will want to read #27, by the way. |
Thank you very much! |
Dear Daniel,I have make the injection script work correctly.And I can set the transmitter number ,got a one-tx & three-rx system .Now I want to know how to set the receiver,and make an SISO system?Looking for your favorite reply.Thank you!
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