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YYD-Master-step1.DSS
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YYD-Master-step1.DSS
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! USED FOR TESTS
Clear
! Modified Kersting YDY Test
! Impedances of the transformer changed per Roger Dugan
! Name changed to reflect that the OpenDSS model is YYD
! Includes scripts for SLG fault cases
New Circuit.YYDTestCase-step1
~ BasekV=69 Bus1=B1 Isc3=1000000 Isc1=1100000 ! near-infinite source
Set Earthmodel=Carson
New Wiredata.ACSR336 GMR=0.0255000 DIAM=0.7410000 RAC=0.3060000 NormAmps=530.0000 Runits=mi radunits=in gmrunits=ft
New Wiredata.ACSR4/0 GMR=0.0081400 DIAM=0.5630000 RAC=0.5920000 NormAmps=340.0000 Runits=mi radunits=in gmrunits=ft
New LineGeometry.Line1-2 nconds=4 nphases=3
~ cond=1 wire=ACSR336 x=-6 h=50 units=ft
~ cond=2 wire=ACSR336 x=-8 h=42 units=ft
~ cond=3 wire=ACSR336 x=8 h=42 units=ft
~ cond=4 wire=ACSR4/0 x=0 h=58 units=ft
~ Reduce=Y
New LineGeometry.Line3-4 nconds=4 nphases=3
~ cond=1 wire=ACSR336 x=-3 h=28 units=ft
~ cond=2 wire=ACSR336 x=-1.5 h=28 units=ft
~ cond=3 wire=ACSR336 x=3 h=28 units=ft
~ cond=4 wire=ACSR4/0 x=0 h=24 units=ft
~ Reduce=Y
New LineGeometry.Line5-6 nconds=3 nphases=3
~ cond=1 wire=ACSR336 x=-7 h=28 units=ft
~ cond=2 wire=ACSR336 x=-4.5 h=28 units=ft
~ cond=3 wire=ACSR336 x=0 h=28 units=ft
// Lines
New Line.TLine1-2 Bus1=B1.1.2.3 Bus2=B2.1.2.3 Geometry=Line1-2 Length=10 units=mi
New Line.DLine3-4 Bus1=B3.1.2.3 Bus2=B4.1.2.3 Geometry=Line3-4 Length=1 units=mi
New Line.DLine5-6 Bus1=B5.1.2.3 Bus2=B6.1.2.3 Geometry=Line5-6 Length=150 units=ft
// The Transformer
// Model as 3 1-phase transformers so we can see the delta currents
New XfmrCode.YYD1Phase phases=1 windings=3
~ conns=[wye wye delta ]
~ kVs=[39.83, 7.62, 2.4]
~ kVAs=[5000 5000 1666] ! 15 MVA 3-phase
~ XHL=7.5 XHT=36 XLT=28
~ %Rs = [0.11 0.11 0.275]
// Connect up the three 1-ph transformer in YYD
New Transformer.YYDA XfmrCode=YYD1Phase ppm=0 !<------------ set ppm
~ Buses=[B2.1.0 B3.1.0 B5.1.2]
New Transformer.YYDB XfmrCode=YYD1Phase ppm=0
~ Buses=[B2.2.0 B3.2.0 B5.2.3]
New Transformer.YYDC XfmrCode=YYD1Phase ppm=0
~ Buses=[B2.3.0 B3.3.0 B5.3.1]
// Loads
New Load.B4a phases=1 Bus1=B4.1.0 kV=7.62 kW=1250 kvar=500 Model=1
New Load.B4b phases=1 Bus1=B4.2.0 kV=7.62 kW=1500 kvar=750 Model=1
New Load.B4c phases=1 Bus1=B4.3.0 kV=7.62 kW=1000 kvar=250 Model=1
New Load.B6 phases=3 Bus1=B6.1.2.3 Model=2 Conn=delta kV=2.4 kW=2250 kvar=1125
Set voltagebases=[69, 13.2, 2.4]
Calcvoltagebases
solve