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\chapter{Black hole formation 2: Vaidya collapse}
\label{s:vai}
\minitoc
\section{Introduction}
Having investigated the gravitational collapse of a star, modelled as a ball of dust,
in the preceding chapter, we move to a much less astrophysical scenario: the
formation of a black hole by the collapse of a spherical shell of pure radiation
(no matter!).
Albeit quite academic, this process illustrates various features of black hole birth and dynamics,
in a way somewhat complementary to the collapse of a dust ball.
The model is based on an exact solution of the Einstein equation sourced by
a pure radial electromagnetic flux, known as \emph{Vaidya metric}, which
we present first (Sec.~\ref{s:vai:Vaidya_metric}).
Then, we introduce the
model describing the implosion of a radiation shell and
study the black hole formation via such a process (Sec.~\ref{s:vai:infall}).
Finally, we focus on a subclass of models giving birth a \emph{naked singularity}, i.e.
such that the central curvature singularity is visible to remote observers located
outside the black hole region (Sec.~\ref{s:vai:naked_sing}).
\section{The ingoing Vaidya metric} \label{s:vai:Vaidya_metric}
\subsection{General expression} \label{s:vai:general}
Let us consider a spherically symmetric spacetime $(\M,\w{g})$ described by
coordinates $(v,r,\th,\ph)$ such that $v\in \R$, $r\in(0, +\infty)$,
$\th\in(0,\pi)$ and $\ph\in(0,2\pi)$, $(\th,\ph)$ being standard
spherical coordinates on $\SS^2$ and $r$ being the areal radius associated
with spherical symmetry (cf. Sec.~\ref{s:sch:static_spher}).
The \defin{ingoing Vaidya metric}\index{ingoing!Vaidya metric}\index{Vaidya!metric!ingoing --}
is the metric tensor
\be \label{e:vai:Vaidya_metric_null}
\encadre{ \w{g} =
-\left( 1 - \frac{2 M(v)}{r} \right)\, \dd v^2
+ 2 \, \dd v \, \dd r
+ r^2 \left( \dd\th^2 + \sin^2\th\, \dd\ph^2 \right) } ,
\ee
where $M(v)$ is a real-valued function of $v$.
We immediately notice that this expression strongly resembles that
of the Schwarzschild metric expressed in the
\emph{null ingoing Eddington-Finkelstein}\index{Eddington-Finkelstein!coordinates}\index{null!ingoing Eddington-Finkelstein coordinates}
coordinates, as given by Eq.~(\ref{e:sch:Schwarz_metric_NIEF}). Actually, the
only difference is the constant $m$ in Eq.~(\ref{e:sch:Schwarz_metric_NIEF})
replaced by the function $M(v)$ in Eq.~(\ref{e:vai:Vaidya_metric_null}).
We may even say that the Schwarzschild metric is the special case $M(v) = \mathrm{const}$ of
the ingoing Vaidya metric.
A key property of the ingoing Vaidya metric is
\begin{prop}[null hypersurfaces $\bm{v = \mathrm{const}}$ and their normals]
\label{p:vai:null_hyp_v_const}
The hypersurfaces $v = \mathrm{const}$ are null (i.e. $v$ is a null coordinate);
a normal to them is the null
vector\footnote{in index notation: $k^\alpha := - g^{\alpha\mu} \partial_\mu v = - \nabla^\alpha v \iff
k_\alpha := - \partial_\alpha v $.}:
\be \label{e:vai:def_k}
\w{k} := - \vp{\dd v} = - \vw{\nabla} v \quad\iff\quad
\uu{k} := - \dd v .
\ee
Moreover, $\w{k}$ is equal to minus the vector $\wpar_r$ of coordinates
$(v,r,\th,\ph)$:
\be \label{e:vai:k_d_dr}
\w{k} = - \left. \der{}{r} \right| _{v,\th,\ph} ,
\ee
where we have rewritten $\wpar_r$ as $\left. \dert{}{r} \right| _{v,\th,\ph}$
to distinguish it from the vector $\wpar_r$ of the IEF coordinates, to be
introduced in Sec.~\ref{s:vai:IEF}.
\end{prop}
\begin{proof}
Let $\Sigma_v$ be a hypersurface defined by $v = \mathrm{const}$.
The metric induced by $\w{g}$ on $\Sigma_v$
is obtained by setting $\dd v = 0$ in Eq.~(\ref{e:vai:Vaidya_metric_null}):
$\left.\w{g}\right| _{\Sigma_v} = r^2 \left( \dd\th^2 + \sin^2\th\, \dd\ph^2 \right)$.
This metric has clearly the signature $(0, +, +)$, i.e. it is degenerate, hence
$\Sigma_v$ is a null hypersurface (cf. Sec.~\ref{s:def:hor_as_null}).
By construction, $\w{k}$ is normal to $\Sigma_v$. It is thus a null vector.
Besides, the metric dual of
the coordinate vector field $\wpar_r$ is the 1-form
$\uu{\wpar_r} = g_{\mu r}\dd x^\mu = g_{vr} \dd v = \dd v = - \uu{k}$,
which proves Eq.~(\ref{e:vai:k_d_dr}).
\end{proof}
\begin{prop}[time orientation of spacetime]
Since $\dd v$ is nowhere vanishing, $\w{k}$ is a nonzero null vector field on $\M$.
We may use it to set the \emph{time orientation} of $(\M,\w{g})$
by declaring that $\w{k}$ is future-oriented (cf. Sec.~\ref{s:fra:time_orientation}).
\end{prop}
As shown in the notebook~\ref{s:sam:Vaidya},
the Ricci tensor of $\w{g}$ takes a simple form:
\be \label{e:vai:Ricci_tensor}
\w{R} = \frac{2 M'(v)}{r^2}\, \dd v \otimes \dd v ,
\ee
where $M'(v)$ stands for the derivative of the function $M(v)$.
The Ricci scalar $R = g^{\mu\nu} R_{\mu\nu} = (2M'(v)/r^2) \, \nabla_\mu v \nabla^\mu v = (2M'(v)/r^2) \, k_\mu k^\mu$ is identically zero, since $\w{k}$ is a null vector.
A consequence is
\begin{prop}[Vaidya metric as a solution of the Einstein equation]
The ingoing Vaidya metric (\ref{e:vai:Vaidya_metric_null}) is a solution
of the Einstein equation (\ref{e:fra:Einstein_eq})
with $\Lambda = 0$ and with the energy-momentum tensor
\be \label{e:vai:ener_mom_tensor}
\encadre{ \w{T} = \frac{M'(v)}{4\pi r^2}\, \uu{k} \otimes \uu{k} } .
\ee
\end{prop}
\begin{remark}
We have already noticed that Vaidya metric reduces to Schwarzschild metric for $M(v) = \mathrm{const}$.
This corresponds to $M'(v) = 0$, so that
Eq.~(\ref{e:vai:ener_mom_tensor}) reduces to $\w{T} = 0$ and we recover that
Schwarzschild metric is a solution of the vacuum Einstein equation.
\end{remark}
The tensor (\ref{e:vai:ener_mom_tensor}) has the same
structure as the energy-momentum tensor of the dust model considered in Chap.~\ref{s:lem}:
$\w{T}_{\rm dust} = \rho \, \uu{u} \otimes \uu{u} $ [Eq.~(\ref{e:lem:T_pressureless})].
The main difference is that $\w{u}$ is a timelike vector (the dust 4-velocity), while
$\w{k}$ is a null vector. For this reason, the energy-momentum tensor (\ref{e:vai:ener_mom_tensor})
is sometimes referred to as a \defin{null dust}\index{null!dust}\index{dust!null --} model \cite{Poiss04}.
It corresponds physically to the energy-momentum tensor of some \emph{monochromatic electromagnetic radiation} in the
\emph{geometrical optics}\index{geometrical optics} approximation (see Box~22.4 of Ref.~\cite{MisneTW73}):
$\w{T}_{\rm rad} = q \, \uu{K} \otimes \uu{K}$, where $q\geq 0$ and $\w{K} := \vw{\nabla}\Phi$ is the \emph{wave vector}\index{wave!vector}, $\Phi$ being the rapidly-varying
phase in the geometrical optics decomposition $\w{A} = \mathrm{Re}(\mathrm{e}^{\mathrm{i}\Phi} \, \w{a})$ of the electromagnetic potential 1-form $\w{A}$. The quantity $q$ is related to the energy density
$\veps$ of the electromagnetic field as measured by an observer $\Obs$ of 4-velocity $\w{u}$
by $\veps = \omega^2 q$, where $\omega = - \w{K}\cdot\w{u}$ is the frequency of the electromagnetic
radiation as measured by $\Obs$.
Maxwell equations\index{Maxwell equations} imply that $\w{K}$ is a null vector and that it is geodesic:
$\w{\nabla}_{\w{K}}\, \w{K} = 0$. The geodesic integral curves of $\w{K}$ are nothing but
the \emph{light rays}\index{light!ray} of the geometrical optics framework.
The geodesic character also holds for $\w{k}$ as defined by Eq.~(\ref{e:vai:def_k}),
since $\w{k}$ is normal to the null hypersurfaces $v = \mathrm{const}$:
the integral curves of $\w{k}$ are the null geodesic generators of these hypersurfaces
(cf. Sec.~\ref{s:def:null_geod_gen}); actually,
we have exactly
\be \label{e:vai:k_geodesic}
\w{\nabla}_{\w{k}}\, \w{k} = 0 .
\ee
This follows from Eq.~(\ref{e:def:wl_geod_kappa}) with $\wl = \w{k}$ and $\kappa = 0$
by virtue of Eq.~(\ref{e:def:def_kappa}) with $\rho=0$ implied by
Eq.~(\ref{e:def:wl_rho_u}) given that $u = v$ and $\w{k} = - \vw{\nabla} v$ [Eq.~(\ref{e:vai:def_k})].
Equations~(\ref{e:vai:k_geodesic}) and (\ref{e:vai:k_d_dr})
imply that the curves $(v,\th,\ph) = \mathrm{const}$
are null geodesics, $\lambda:=-r$ is an affine parameter along them and $\w{k}$ is
the corresponding tangent vector.
Another condition for the identification of $\w{T}$ with $\w{T}_{\rm rad}$ is that the coefficient
in front of $\uu{k} \otimes \uu{k}$ in (\ref{e:vai:ener_mom_tensor})
is non-negative, since $q\geq 0$ in $\w{T}_{\rm rad}$. This constraint can also be seen as the \emph{null energy condition}\index{null!energy condition}\index{energy!condition!null --} (\ref{e:neh:null_energy_cond_matter}) introduced in
Sec.~\ref{s:def:null_convergence_cond}: for any null vector $\wl$, we have
$\w{T}(\wl,\wl) = M'(v)/(4\pi r^2)\, (\w{k}\cdot\wl)^2$ and hence $\w{T}(\wl,\wl) \geq 0$ $\iff$
$M'(v) \geq 0$. In other words, the function $M(v)$ must be monotically increasing. Then, we can set
$\w{k} = \alpha \w{K}$, where $\alpha$ is a constant, to have a perfect match of (\ref{e:vai:ener_mom_tensor}) with the electromagnetic radiation energy-momentum
tensor $\w{T}_{\rm rad}$.
To summarize:
\begin{prop}[Vaidya metric sourced by electromagnetic radiation]
\label{p:vai:source_Vaidya_metric}
Provided that $M(v)$ is an increasing function\footnote{by \emph{increasing}, it is meant
strictly increasing ($M'(v)>0$) or locally constant ($M'(v) = 0$).},
the ingoing Vaidya spacetime $(\M,\w{g})$ is generated by a spherical symmetric electromagnetic radiation
within the geometrical optics approximation. The corresponding light rays are the
\defin{ingoing radial null geodesics}\index{ingoing!radial!null geodesics}
$\Li^{\rm in}_{(v,\th,\ph)}$
defined by $v=\mathrm{const}$, $\th=\mathrm{const}$ and $\ph=\mathrm{const}$.
These geodesics admit $\w{k}$ as the tangent vector associated with their affine parameter
$\lambda := -r$.
\end{prop}
\begin{hist} \label{h:vai:origin}
The Vaidya metric has been actually first derived by Henri Mineur\index[pers]{Mineur, H.} in 1933 \cite{Mineu1933},
as the solution of the Einstein equation for the exterior of a spherically symmetric body,
the ``mass'' of which ``is varying''
due to the radiation of an ``energy flux of light''. It thus corresponds to the \emph{outgoing}
version of the Vaidya metric, while the version (\ref{e:vai:Vaidya_metric_null})
considered here is \emph{ingoing}. More precisely, the solution given by Mineur
reads\footnote{This is Mineur's Eq.~(21), p.~47 of Ref.~\cite{Mineu1933}.
The minus sign in the left-hand side, which is present
Mineur's article~\cite{Mineu1933}, is fortunate for comparison with the current text
since Mineur is using the metric signature $(+,-,-,-)$, i.e. the opposite of ours.}
\be \label{e:vai:Mineur_metric}
-\D s^2 = 2 \, \D x \, \D r + r^2 \, \frac{\D u^2 - \D v^2}{u^2} - \left( 1 - \frac{2 M(x)}{r} \right) \D x^2 .
\ee
The coordinate $x$ is the opposite of a retarded time ($x = -u$ in our notations), while $(u,v)$ are coordinates on the 2-sphere $\SS^2$ (submanifold $(x,r) = \mathrm{const}$)
such that the standard (round)
metric of $\SS^2$ is $\w{q} = u^{-2} \left( - \dd u^2 + \dd v^2 \right)$
(cf. the unnumbered equation at the top of p.~35 of Mineur's article \cite{Mineu1933}).
This looks quite surprising, given that $u^{-2} \left( - \dd u^2 + \dd v^2 \right)$
is rather the metric of the 2-dimensional anti-de Sitter space expressed in a variant
of Poincaré coordinates (compare Eq.~(\ref{e:exk:metric_AdS2}) with $T = v$ and $R = 1/u$).
In particular the signature is $(-, +)$, while it should be $(+,+)$ for
$\SS^2$! It turns out that the coordinate $u$ used by Mineur is pure imaginary,
i.e. Mineur wrote the metric of $\SS^2$ via a kind of Wick rotation of
the metric of the hyperbolic plane\index{hyperbolic!plane}\footnote{The spaces $\mathbb{H}^2$ and $\SS^2$
are somehow connected as being the only 2-dimensional Riemannian manifolds of
nonzero constant scalar curvature (negative for $\mathbb{H}^2$ and positive for $\SS^2$).}
$\mathbb{H}^2$, the latter being
$(\dd X^2 + \dd Y^2)/Y^2$: setting $v = X$ and $u = \mathrm{i} Y$, one
gets $-\w{q} = u^{-2} \left( \dd u^2 - \dd v^2 \right)$. If one restores
the standard spherical coordinates $(\th,\ph)$ on $\SS^2$ and uses the modern notation
$u = -x$ as well as the metric signature $(-,+,+,+)$, one can rewrite Mineur's
solution as\footnote{As one can infer by comparing with other expressions
of $\D s^2$ in Mineur's article, the $+$ sign in front of $r^2$ times the $\SS^2$
line element in Eq.~(\ref{e:vai:Mineur_metric}) is certainly a typo and should be
replaced by a $-$ sign; this correction is performed to get Eq.~(\ref{e:vai:Mineur_metric_modern}).}
\be \label{e:vai:Mineur_metric_modern}
\w{g} = -\left( 1 - \frac{2 M(u)}{r} \right)\, \dd u^2
- 2 \, \dd u \, \dd r
+ r^2 \left( \dd\th^2 + \sin^2\th\, \dd\ph^2 \right) .
\ee
This ressembles the metric (\ref{e:vai:Vaidya_metric_null}).
The only difference is the $-$ sign in front of $\dd u \, \dd r$, while there is a $+$ sign
in front $\dd v \, \dd r$ in (\ref{e:vai:Vaidya_metric_null}). This results from Mineur's version
being \emph{outgoing}, given that he considered a radiating body. On
the contrary, the version (\ref{e:vai:Vaidya_metric_null}) is \emph{ingoing}, since we are interested in gravitational collapse and black hole formation.
Twenty years later, in 1953, Prahalad Chunnilal Vaidya\index[pers]{Vaidya, P.C.} presented
the metric that bears his name in the form (\ref{e:vai:Mineur_metric_modern}) \cite{Vaidy53}.
Previously, in 1943 \cite{Vaidy43} and in 1951 \cite{Vaidy51a}, Vaidya presented
the metric outside a spherically symmetric radiating star in an equivalent, but
more complicated form:
\be \label{e:vai:Vaidya_metric_original}
\w{g} = - \frac{1}{f(M)^2} \left( \der{M}{T} \right) ^2
\left(1 - \frac{2 M}{r} \right) \, \dd T^2
+ \left(1 - \frac{2 M}{r} \right) ^{-1} \dd r^2
+ r^2 \left( \dd\th^2 + \sin^2\th\, \dd\ph^2 \right) ,
\ee
where $f$ is an arbitrary function and $M = M(T, r)$ fulfills the differential equation
$\dert{M}{r}\, (1 - {2 M}/{r}) = f(M)$.
By introducing the scalar field $u$ such that $\dd u = - f(M)^{-1} \dd M$
and promoting it as a coordinate, one can
bring this solution to Mineur's form (\ref{e:vai:Mineur_metric_modern}).
In a foreword to Vaidya's 1951 article \cite{Vaidy51a},
Vishnu Vasudev Narlikar\index[pers]{Narlikar, V.V.}, who was Vaidya's PhD advisor,
wrote: \emph{``The treatment as given here is essentially different from that of Professor H. Mineur
as it appears in Ann. de l'Ecole Normal Superieure, Ser. 3, 5, 1, 1933
\emph{(our Ref. \cite{Mineu1933})}. Our attention
was kindly drawn to it by Professor Mineur some years ago.''} In a common article by
Narlikar and Vaidya published in 1947 \cite{NarliV1947}, one can also read
\emph{``The line element (5) \emph{[our Eq.~(\ref{e:vai:Vaidya_metric_original})]}
was first published by one of us some years ago. A line element equivalent to
(5) but not obviously so was obtained by Mineur
several years earlier.''} It would probably be fair to call the metric
(\ref{e:vai:Mineur_metric_modern}) the \emph{Mineur-Vaidya metric}; we shall
however keep here the usual name of \emph{Vaidya metric}.
The metric (\ref{e:vai:Mineur_metric_modern}) was popularized and further studied by Richard W. Lindquist\index[pers]{Lindquist, R.W.}, Robert A. Schwartz\index[pers]{Schwartz, R.A} and Charles W. Misner\index[pers]{Misner, C.W.}
in 1965 \cite{LindqSM65}, who apparently were not aware of Mineur's work.
\end{hist}
\subsection{Expression in ingoing Eddington-Finkelstein coordinates} \label{s:vai:IEF}
To deal with black hole formation in Vaidya spacetime, it is quite
convenient to work with the
\defin{ingoing Eddington-Finkelstein (IEF) coordinates}\index{Eddington-Finkelstein!coordinates}\index{ingoing!Eddington-Finkelstein!coordinates}\index{IEF}
$(t,r,\th,\ph)$, which are defined from the null coordinates $(v,r,\th,\ph)$ in the
same way as in the Schwarzschild case, i.e. by considering that $v$ is the
\defin{advanced time}\index{advanced!time}\index{time!advanced --} with respect to $t$
[cf. Eq.~(\ref{e:sch:ti_v_r})]:
\be \label{e:vai:t_v_r}
\encadre{t := v - r} \iff \encadre{v = t + r} .
\ee
\begin{remark}
The coordinate $t$ was denoted by $\ti$ in Chap.~\ref{s:sch}, where $t$
was reserved for the Schwarzschild-Droste time coordinate.
\end{remark}
We have $\dd v = \dd t + \dd r$, from which the IEF expression of the
metric tensor is immediately deduced from Eq.~(\ref{e:vai:Vaidya_metric_null}):
\be \label{e:vai:metric_IEF}
\encadre{
\begin{array}{ll}
\w{g} = &
\displaystyle -\left( 1 - \frac{2 M(t+ r)}{r} \right)\, \dd t^2
+ \frac{4 M(t + r)}{r} \, \dd t \, \dd r
+ \left( 1 + \frac{2 M(t+r)}{r} \right)\, \dd r^2 \\[1ex]
& + r^2 \left( \dd\th^2 + \sin^2\th\, \dd\ph^2 \right) .
\end{array}
}
\ee
The expression of $\w{k}$ in terms of the IEF coordinate frame
is deduced from Eq.~(\ref{e:vai:k_d_dr}) and the chain rule:
\be \label{e:vai:k_IEF}
\w{k} = \wpar_t - \wpar_r .
\ee
\begin{remark}
The analog equation in Schwarzschild spacetime is Eq.~(\ref{e:sch:null_vector_k}).
\end{remark}
\subsection{Outgoing radial null geodesics}
Let us determine the radial null directions at each point by searching for
null vectors of the form $\wl = \wpar_t + V \wpar_r$. The condition
$\w{g}(\wl, \wl) = 0$ with the expression (\ref{e:vai:metric_IEF}) for
$\w{g}$ yields immediately a quadratic equation for $V$:
\[
\left( 1 + \frac{2 M(t+r)}{r} \right) V^2
+ \frac{4 M(t + r)}{r}\, V +
1 - \frac{2 M(t+ r)}{r} = 0 .
\]
The two solutions are $V = -1$ and $V = [r - 2M(t + r)]/[r + 2M(t+r)]$.
The first solution gives back the ingoing null vector $\w{k}$ introduced in Sec.~\ref{s:vai:general}
[cf. Eq.~(\ref{e:vai:k_IEF})].
The null vector $\wl$ corresponding to the second solution is
\be
\wl = \wpar_t + \frac{r - 2M(t + r)}{r + 2M(t+r)}\, \wpar_r .
\ee
\begin{prop}[radial null geodesics]
The integral curves of the vector fields $\w{k}$ and $\wl$ are null geodesics.
Those of $\w{k}$ are the \emph{ingoing radial null geodesics}\index{ingoing!radial!null geodesic}
$\Li^{\rm in}_{(v,\th,\ph)}$ already discussed in Sec.~\ref{s:vai:general},
while those of $\wl$ are called the \defin{outgoing radial null geodesics}\index{ingoing!null geodesic}.
\end{prop}
\begin{proof}
A direct computation shows that $\wl$ is a pregeodesic vector field:
$\wnab_{\wl} \wl = \kappa \wl$, with $\kappa = - 4 [rM'(t+r) - M(t+r)]/[r + 2M(t+r)]^2$
(cf. the notebook~\ref{s:sam:Vaidya}). It follows that the integral curves of
$\wl$ are geodesics (cf. Sec.~\ref{s:geo:gener_param}).
\end{proof}
The differential equation governing the outgoing radial null geodesics
is obtained by demanding that $\wl$ is their tangent vector:
\be \label{e:vai:ODE_outgoing_null}
\encadre{ \frac{\D r}{\D t} = \frac{r - 2M(t + r)}{r + 2M(t+r)} }.
\ee
In what follows, we shall get exact solutions of this equation for $M(v)$ piecewise linear.
\begin{remark}
As in the Schwarzschild case (cf. Remark~\ref{r:sch:outgoing_ingoing}
on p.~\pageref{r:sch:outgoing_ingoing}),
the outgoing radial null geodesics are actually \emph{ingoing}, i.e. have $r$ decreasing towards the future,
as soon as $r < 2 M(t+r)$. This corresponds to the region bounded by the red curve in Fig.~\ref{f:vai:diag_S0}, to be discussed in Sec.~\ref{s:vai:trapped_surf}.
\end{remark}
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
\section{Imploding shell of radiation} \label{s:vai:infall}
\subsection{The imploding shell model} \label{s:vai:imploding_shell}
An \defin{imploding shell of radiation}\index{shell!imploding -- of radiation}\index{imploding!shell of radiation}
is defined by the ingoing Vaidya metric with the function $M(v)$ obeying
$M'(v) \neq 0$ only on a finite interval of $v$. By choosing properly
the origin of $v$, we may consider this interval to be $[0, v_0]$, where
the parameter $v_0>0$ governs the shell's thickness.
The function $M(v)$ is thus constant outside the interval $[0, v_0]$.
In order to describe the formation of a black hole, we choose
$M(v) = 0$ for $v < 0$. This corresponds to a piece of Minkowski spacetime,
since the metric (\ref{e:vai:metric_IEF})
clearly reduces to Minkowski metric (\ref{e:glo:Mink_metric_spher}) wherever $M(v)=0$.
Denoting by $m>0$ the constant value of $M(v)$ for $v > v_0$, we have then
\be \label{e:vai:mass_function}
\encadre{ M(v) = \left\{ \begin{array}{ll}
0 \quad \mbox{for} \ v < 0 \qquad & (\mbox{Minkowski region},\ \M_{\rm Min}) \\
m \, S(v/v_0) \quad \mbox{for} \ 0 \leq v \leq v_0
& (\mbox{radiation region},\ \M_{\rm rad}) \\
m \quad \mbox{for} \ v > v_0 \qquad & (\mbox{Schwarzschild region},\ \M_{\rm Sch}),
\end{array} \right. }
\ee
where $S: [0,1] \to [0,1],\ x \mapsto S(x)$ is an increasing function
obeying $S(0) = 0$ and $S(1) = 1$.
The region with $v>v_0$ is qualified as \emph{Schwarzschild} since for $M(v) = m = \mathrm{const}$,
the Vaidya metric reduces to Schwarzschild metric, as noticed
in Sec.~\ref{s:vai:general}.
The three regions are shown in terms of coordinates $(t, r)$ on Fig.~\ref{f:vai:diag_S0}:
$\M_{\rm rad}$ (the imploding shell) is the yellow region, $\M_{\rm Min}$ lies below it and
$\M_{\rm Sch}$ lies above it.
\begin{figure}
\centerline{\includegraphics[width=0.6\textwidth]{vai_diag_S0.pdf}}
\caption[]{\label{f:vai:diag_S0} \footnotesize
Spacetime diagram of the Vaidya collapse based on the IEF coordinates $(t, r)$
and for the linear mass function $M(v)=m v/v_0$ with $v_0 = 3 m$
(homothetic model with $\alpha = 2/3$).
The yellow area is the radiation region $\M_{\rm rad}$
[cf. Eq.~(\ref{e:vai:mass_function})],
below it lies the Minkowski region $\M_{\rm Min}$
and above it, the Schwarzschild region $\M_{\rm Sch}$.
The solid (resp. dashed) green curves are outgoing (resp. ingoing) radial
null geodesics. The thick black line marks the event horizon $\Hor$ (Sec.~\ref{s:vai:BH_formation}) and
the red one the future outer trapping horizon $\mathscr{T}$ (Sec.~\ref{s:vai:trapped_surf}).
Note that $\Hor$ and $\mathscr{T}$ coincide in $\M_{\rm Sch}$.
The curvature singularity
is indicated by the orange zigzag line. The part of the figure corresponding
to $\M_{\rm Min}$ can be compared with Fig.~\ref{f:glo:null_coord},
while that corresponding to $\M_{\rm Sch}$ can be
compared with Fig.~\ref{f:sch:rad_null_geod_EF}.
\textsl{[Figure generated by the notebook \ref{s:sam:Vaidya}]}
}
\end{figure}
The simplest example of a function $M(v)$
obeying (\ref{e:vai:mass_function}) is obtained for $S(x) = x$:
\be \label{e:vai:S_linear}
S(x) = x \quad \iff \quad M(v) = m \frac{v}{v_0} \quad (0 \leq v \leq v_0).
\ee
It is shown as the blue curve in Fig.~\ref{f:vai:mass_function}.
This choice of $S$ makes $M(v)$ piecewise linear. The resulting metric tensor
(\ref{e:vai:Vaidya_metric_null}) is continuous but not $C^1$ at $v=0$ and $v=v_0$. A choice
of $S$ that yields a $C^2$ metric tensor is $S(x) = 6 x^5 - 15 x^4 + 10 x^3$.
This choice is depicted by the red curve in Fig.~\ref{f:vai:mass_function}.
\begin{figure}
\centerline{\includegraphics[width=0.6\textwidth]{vai_mass_function.pdf}}
\caption[]{\label{f:vai:mass_function} \footnotesize
Function $M(v)$ for the imploding shell model, for $v_0 = 3 m$ and
two different choices of $S(x)$ in formula~(\ref{e:vai:mass_function}).
}
\end{figure}
\begin{hist}
The imploding shell model (\ref{e:vai:mass_function})
has been introduced by William A. Hiscock\index[pers]{Hiscock, W.A.}, Leslie G. Williams\index[pers]{Williams, L.G.} and Douglas M. Eardley\index[pers]{Eardley, D.M.} in 1982 \cite{HiscoWE82},
as well as by Achilles Papapetrou\index[pers]{Papapetrou, A.} in 1985 \cite{Papap85}.
Both studies regarded the specific case $S(x) = x$. Hiscock et al. considered
the ingoing Vaidya metric in the form (\ref{e:vai:Vaidya_metric_null}) (coordinates $(v, r, \th, \ph)$),
while Papapetrou made use of the form (\ref{e:vai:metric_IEF}) (coordinates $(t, r, \th,\ph)$).
\end{hist}
\subsection{Solution for $M(v)$ piecewise linear} \label{s:vai:sol_M_linear}
Let us consider the simplest choice for $M(v)$, i.e.
Eq.~(\ref{e:vai:S_linear}).
In the radiation region, the metric tensor (\ref{e:vai:Vaidya_metric_null})
takes the form
\be \label{e:vai:self_similar_metric}
\w{g} = -\left( 1 - \alpha \frac{v}{r} \right)\, \dd v^2
+ 2 \, \dd v \, \dd r
+ r^2 \left( \dd\th^2 + \sin^2\th\, \dd\ph^2 \right) \qquad
(0 \leq v \leq v_0),
\ee
where $\alpha$ is the positive constant defined by
\be \label{e:vai:def_alpha}
\encadre{ \alpha := \frac{2m}{v_0} }.
\ee
It is immediately apparent on (\ref{e:vai:self_similar_metric})
that for any $\lambda > 0$, the homothety $H_\lambda:\ (v, r) \mapsto (\lambda v, \lambda r)$
maps $\w{g}$ to $\lambda^2 \w{g}$. Hence $H_\lambda$ is a
conformal isometry\index{conformal!isometry}\index{isometry!conformal --} of
$(\M_{\rm rad},\w{g})$ with a constant conformal factor $\lambda^2$. The homotheties $(H_\lambda)_{\lambda\in \R_{>0}}$
form a 1-dimensional
group, the generator of which is obtained by considering infinitesimal transformations,
i.e. homotheties of ratio $\lambda = 1 + \D\lambda$ where $\D\lambda$ is
infinitely small. The components of the corresponding displacement vector are $\D v = \D\lambda \, v$
and $\D r = \D\lambda\, r$, so that formula~(\ref{e:neh:xi_dxdt}) (with $t \leftrightarrow \lambda$)
leads to the generator
\be \label{e:vai:hom_Killing}
\w{\xi} = v \, \wpar_v + r \left. \wpar_r \right| _{v,\th,\ph}
= t \, \wpar_t + r \, \wpar_r .
\ee
The second equality follows form the change of coordinates (\ref{e:vai:t_v_r}).
That $\w{\xi}$ has the same expression with respect to $(v, r)$ and $(t, r)$
coordinates should not be surprising since the homothety $H_\lambda$ has the
same expression in both coordinate systems: $H_\lambda:\ (t, r) \mapsto (\lambda t, \lambda r)$,
given that $\lambda v = \lambda(t + r) = \lambda t + \lambda r$.
The vector field $\w{\xi}$ is called a
\defin{homothetic Killing vector}\index{homothetic!Killing!vector}\index{Killing!vector!homothetic --}.
The Lie derivative of $\w{g}$ along $\w{\xi}$ is twice $\w{g}$ (cf. the notebook~\ref{s:sam:Vaidya}
for the computation):
\be \label{e:vai:Lie_xi_g}
\Lie{\xi} \w{g} = 2 \w{g} .
\ee
We shall refer to the choice $M(v)$ piecewise linear
as the \defin{homothetic radiation shell model}\index{homothetic!radiation shell}.
\begin{remark}
The denomination \defin{self-similar}\index{self-similar Vaidya spacetime},
in place of \emph{homothetic},
is also used in the literature (e.g. \cite{Nolan01,Nolan07}).
\end{remark}
\begin{remark}
A \emph{homothetic Killing vector} is not a \emph{Killing vector},
for the right-hand side of Eq.~(\ref{e:vai:Lie_xi_g}) would be zero if
$\w{\xi}$ were a Killing vector [cf. Eq.~(\ref{e:neh:Lie_xi_g})].
In other words, except for $\lambda=1$, the homotheties $H_\lambda$ are not isometries,
but only \emph{conformal isometries}.
Generally, vector fields generating conformal isometries are
called \defin{conformal Killing vectors}\index{conformal!Killing vector}.
They fulfill $\Lie{\xi} \w{g} = \sigma \w{g}$, where $\sigma$ is a scalar field.
Equation~(\ref{e:vai:Lie_xi_g}) constitutes the particular case $\sigma = 2$.
\end{remark}
Let us introduce the variable
\be \label{e:vai:def_x_v_r}
\encadre{ x := \frac{v}{r} },
\ee
which is invariant under the homotheties $H_\lambda$.
The differential equation governing the outgoing radial null
geodesics, Eq.~(\ref{e:vai:ODE_outgoing_null}),
can be rewritten as $\D t / \D r = (1 + \alpha x)/(1 - \alpha x)$ [cf. Eq.~(\ref{e:vai:def_alpha})].
Given that $t = v - r = r(x - 1)$ implies $\D t / \D r = x - 1 + r \D x/\D r$,
we get the equivalent form
\be \label{e:vai:ODE_outgoing_x}
r \frac{\D x}{\D r} = \frac{\alpha x^2 - x + 2}{1 - \alpha x} .
\ee
Fortunately, this ordinary differential equation is separable, so that its
solutions are easily obtained by quadrature. They depend on whether the
quadratic polynomial $P_\alpha(x) := \alpha x^2 - x + 2$ admits real roots
or not.
Let us first focus on the case where $P_\alpha$ has no real root.
The discriminant being $1 - 8\alpha$, this occurs if, and only if,
\be \label{e:vai:v0_small}
\alpha > \frac{1}{8} \iff v_0 < 16 \, m .
\ee
By considering the energy-momentum tensor (\ref{e:vai:ener_mom_tensor}) with
expression (\ref{e:vai:S_linear}) substituted for $M(v)$, we get
\be \label{e:vai:T_alpha}
\w{T} = \frac{\alpha}{8\pi r^2}\, \uu{k} \otimes \uu{k} .
\ee
Consequently, we may say that the case $\alpha > 1/8$
corresponds to
a \defin{large radiation energy density}\index{radiation!energy density}.
We shall discuss the low radiation energy density case
($\alpha < 1/8$)
in Sec.~\ref{s:vai:naked_sing}.
For the moment, assuming (\ref{e:vai:v0_small}),
we have $P_\alpha(x) > 0$ for any $x\in\R$ and we may rewrite Eq.~(\ref{e:vai:ODE_outgoing_x})
as
\be \label{e:vai:ODE_outgoing_x_sep}
\D \ln r = \frac{1 - \alpha x}{\alpha x^2 - x + 2}\, \D x ,
\ee
the solution of which is $r = r_0 f_\alpha(x)$, where
\be \label{e:vai:lnf_alpha}
\ln f_\alpha(x) := \int_0^x \frac{1 - \alpha x'}{\alpha {x'}^2 - x' + 2}\, \D x'
\ee
and the integration constant $r_0>0$ is the value of $r$ at $x=0$, or equivalently
at $v = 0$, since $f_\alpha(0) = 1$.
Explicitly,
\be \label{e:vai:sol_r_x_v0_small}
\encadre{ f_\alpha(x) = \frac{\sqrt{2}}{\sqrt{\alpha x^2 - x + 2}}
\exp\left\{ \frac{1}{\sqrt{8\alpha - 1}} \left[
\arctan \left(\frac{2\alpha x - 1}{\sqrt{8\alpha - 1}} \right)
+ \arctan\left( \frac{1}{\sqrt{8\alpha - 1}} \right)\right] \right\} },
\ee
Introducing the dimensionless
parameter $u := - \ln (r_0 / m)$, we conclude:
\begin{prop}[outgoing radial null geodesics for the $\bm{\alpha > 1/8}$ homothetic shell]
For the homothetic model with $\alpha > 1/8$,
the outgoing radial null geodesics in $\M_{\rm rad}$
form a 3-parameter family of curves $\left(\Li_{(u,\th,\ph)}^{\rm out}\right)$,
where the parameter $u \in \R$ is related to the value $r_0$ of $r$
at the inner edge of the radiation shell ($v=0$) by $r_0 = m \mathrm{e}^{-u}$.
The parametric equation of $\Li_{(u,\th,\ph)}^{\rm out}$ in terms of the IEF
coordinates is
\be \label{e:vai:eq_out_v0_small}
\begin{cases}
t = m \mathrm{e}^{-u} (x - 1) f_\alpha(x) \\
r = m \mathrm{e}^{-u} f_\alpha(x) \\
\th = \mathrm{const}, \ph = \mathrm{const}
\end{cases}
\qquad 0 \leq x \leq x_{\rm max},
\ee
where the function $f_\alpha(x)$ is defined by Eq.~(\ref{e:vai:sol_r_x_v0_small})
and either $x_{\rm max} = +\infty$ ($\Li_{(u,\th,\ph)}^{\rm out}$ reaches $r=0$ for some $v < v_0$)
or $x_{\rm max}$ is the solution of $m \mathrm{e}^{-u} x_{\rm max} f_\alpha(x_{\rm max}) = v_0$
($\Li_{(u,\th,\ph)}^{\rm out}$ reaches the outer edge of the radiation shell).
\end{prop}
The function $f_\alpha(x)$ is plotted in Fig.~\ref{f:vai:f_alpha_x}.
It increases from $1$ at $x=0$ to some maximum reached for $x=\alpha^{-1}$
and then decreases to $0$ as $x\to +\infty$. This behavior follows
directly from the sign of the numerator $1 - \alpha x$ in Eq.~(\ref{e:vai:ODE_outgoing_x_sep}),
given that the denominator $\alpha x^2 - x + 2$ is always positive for $\alpha > 1/8$.
Note that it could be that $x_{\rm max} < \alpha^{-1}$ so that the maximum
of $f_\alpha(x)$ is actually not reached along $\Li_{(u,\th,\ph)}^{\rm out}$. In that
case, $r$ increases monotonically along $\Li_{(u,\th,\ph)}^{\rm out}$ in $\M_{\rm rad}$,
from $r_0$ to $r_0 f_\alpha(x_{\rm max})$.
\begin{figure}
\centerline{\includegraphics[width=0.6\textwidth]{vai_f_alpha_x.pdf}}
\caption[]{\label{f:vai:f_alpha_x} \footnotesize
Function $f_\alpha(x)$, defined by Eq.~(\ref{e:vai:sol_r_x_v0_small}),
for some selected values of $\alpha > 1/8$. For each value of $\alpha$, the maximum
of $f_\alpha(x)$ is achieved for $x=\alpha^{-1}$.
\textsl{[Figure generated by the notebook \ref{s:sam:Vaidya_solve_ode_out}]}
}
\end{figure}
It appears clearly on Eq.~(\ref{e:vai:eq_out_v0_small}) that
the homothety $H_\lambda:\ (t, r) \mapsto (\lambda t, \lambda r)$
transforms the geodesic $\Li_{(u,\th,\ph)}^{\rm out}$ into the geodesic
$\Li_{(u',\th,\ph)}^{\rm out}$ with $u' = u - \ln \lambda$,
in agreement with the homothetic symmetry of $(\M_{\rm rad}, \w{g})$ discussed
above.
Some outgoing radial null geodesics are depicted as solid green lines
in Fig.~\ref{f:vai:diag_S0}. In $\M_{\rm rad}$, they obey
Eq.~(\ref{e:vai:eq_out_v0_small}).
Note that the homothetic symmetry appears clearly on the figure.
If a geodesic $\Li_{(u,\th,\ph)}^{\rm out}$ has a $r$-turning point in $\M_{\rm rad}$,
it must located at $x = \alpha^{-1}$, i.e. at $t/r = \alpha^{-1} - 1$,
or equivalently at
\be \label{e:vai:r_max_out}
t = \left( \frac{v_0}{2m} - 1 \right) r .
\ee
The above equation defines a straight line through $(t,r) = (0,0)$,
whose intersection with $\M_{\rm rad}$ is depicted by a red segment
in Fig.~\ref{f:vai:diag_S0}.
\begin{remark}
The turning point value (\ref{e:vai:r_max_out}) can be obtained
directly by setting $\D r / \D t = 0$ in Eq.~(\ref{e:vai:ODE_outgoing_null})
and using the value (\ref{e:vai:S_linear}) for $M(v)$.
\end{remark}
In the Minkowski region, the outgoing radial null geodesics are straight line
segments inclined at $+45^\circ$ in Fig.~\ref{f:vai:diag_S0}, while
in the Schwarzschild region, they are curves obeying Eq.~(\ref{e:sch:outgoing_null_geod_EF})
(with the change of notation $\ti \leftrightarrow t$).
\subsection{Black hole formation} \label{s:vai:BH_formation}
In spherical symmetry, the inspection of radial null geodesics provides
a direct access to the black hole event horizon $\Hor$.
Since we have at disposal the exact solution
(\ref{e:vai:eq_out_v0_small}) for the outgoing radial null geodesics,
let us determine the location of $\Hor$ for the homothetic
shell collapse.
We arrive at the following result:
\begin{prop}[black hole formation for the $\bm{\alpha > 1/8}$ homothetic shell]
The homothetic imploding radiation shell with $\alpha := 2m/v_0 > 1/8$
generates a black hole. The black hole event horizon $\Hor$
is the future light cone of the point of IEF coordinates
$(t, r) = (t_{\rm hb}, 0)$, with\footnote{As in Chap.~\ref{s:lem}, the subscript `hb' stands
for \emph{horizon birth}.}
\be \label{e:vai:t_hb}
\encadre{ t_{\rm hb} = - 4 m \exp \left[ - \frac{2}{\sqrt{8\alpha - 1}}
\arctan\left( \frac{1}{\sqrt{8\alpha - 1}} \right) \right] } .
\ee
Outside the radiation shell, $\Hor$ coincides with the
Killing horizon of Schwarzschild spacetime located at $r=2m$.
\end{prop}
\begin{figure}
\centerline{\includegraphics[width=0.6\textwidth]{vai_thb_v0.pdf}}
\caption[]{\label{f:vai:thb_v0} \footnotesize
Value $t_{\rm hb}$ of the coordinate $t$ at the black hole birth [Eq.~(\ref{e:vai:t_hb})]
as a function of the radiation shell thickness $v_0$, for
the homothetic shell collapse [Eq.~(\ref{e:vai:S_linear})].
}
\end{figure}
\begin{proof}
In the Schwarzschild region $\M_{\rm Sch}$, the Killing horizon is the hypersurface
$r = 2m$. It is generated by the null geodesics $\Li^{{\rm out},\Hor}_{(\th,\ph)}$
discussed in Sec.~\ref{s:sch:radial_null_IEF} [cf. Eq.~(\ref{e:sch:outgoing_null_geod_H})].
Let us consider one such geodesic, $\hat{\Li}$ say.
It has a fixed value of $(\th,\ph)$ and, when followed in the past direction,
it encounters the outer edge of the radiation region $\M_{\rm rad}$
(hypersurface $v=v_0$) at the point $A$ such that $r_A = 2m$ and $t_A = v_0 - 2m$
(cf. Fig.~\ref{f:vai:diag_S0}, where $\hat{\Li}$ can be identified with the
black curve). If $\hat{\Li}$ is prolonged into $\M_{\rm rad}$, still in the past direction, it encounters the inner edge of $\M_{\rm rad}$ (hypersurface $v=0$) at the point $B$
(cf. Fig.~\ref{f:vai:diag_S0}).
The portion $AB$ of $\hat{\Li}$ coincides with the geodesic $\Li_{(u_B,\th,\ph)}^{\rm out}$
of the outgoing radial null family given by Eq.~(\ref{e:vai:eq_out_v0_small}),
with $u_B = - \ln(r_B / m)$ (since $f_\alpha(x_B)=1$, given that $x_B = 0$).
We have then $r_A = r_B f_\alpha(x_A)$.
Now, by definition of $x$ [Eq.~(\ref{e:vai:def_x_v_r})] and
$\alpha$ [Eq.~(\ref{e:vai:def_alpha})],
$x_A = v_A / r_A = v_0 / (2m) = \alpha^{-1}$.
We have thus $2 m = r_B f_\alpha(\alpha^{-1})$. In view of expression
(\ref{e:vai:sol_r_x_v0_small}) for $f_\alpha(x)$, there comes
\[
r_B = 2 m \exp \left[ - \frac{2}{\sqrt{8\alpha - 1}}
\arctan\left( \frac{1}{\sqrt{8\alpha - 1}} \right) \right] .
\]
Since $B$ is located on the hypersurface $v=0$, we have $t_B = - r_B$.
If the radial null geodesic $\hat{\Li}$
is prolonged further to the past in the Minkowski
region $\M_{\rm Min}$, it becomes the straight line of equation $t = r - 2 r_B$.
$\hat{\Li}$ thus reaches $r=0$ at some event $C$ of
coordinate $t = t_{\rm hb} = -2 r_B$, hence Eq.~(\ref{e:vai:t_hb}).
There remains to prove that the null hypersurface generated by
$\hat{\Li}$ when $(\th,\ph)$ varies, i.e. the future light cone $\Hor$
of the point $(t, r) = (t_{\rm hb}, 0)$, is indeed the black hole event
horizon. To this aim, let us consider an outgoing radial null geodesic $\Li$
in $\M_{\rm Min}$ such that $\Li$ crosses $r=0$ at $t < t_{\rm hb}$,
i.e. outside $\Hor$.
$\Li$ arrives then at the inner edge of $\M_{\rm rad}$
with $r = r_0 > r_B$. In $\M_{\rm rad}$,
according to Eq.~(\ref{e:vai:eq_out_v0_small}),
$\Li$ is homothetic to a part of $\hat{\Li}$ with a ratio $r_0 / r_B > 1$. Hence it emerges
at the outer edge of $\M_{\rm rad}$ with $r > r_A = 2 m$. $\Li$ is
there in the exterior of the Schwarzschild black hole, so that it will subsequently reach
the future null infinity $\scri^+$ of $\M_{\rm Sch}$.
On the contrary, if $\Li$ crosses $r=0$ with $t > t_{\rm hb}$,
i.e. inside $\Hor$,
it encounters the inner edge of $\M_{\rm rad}$ with
$r = r_0 < r_B$. A part of $\Li$ is then homothetic to the segment $BA$ of
$\hat{\Li}$ with a ratio $r_0 / r_B < 1$. Then either (i) $\Li$ has a
$r$-turning point and reaches $r=0$
in $\M_{\rm rad}$ or (ii) $\Li$ reaches
the outer edge of $\M_{\rm rad}$ ($v = v_0$) at some point $A'$.
Given that $x_A = \alpha^{-1}$ corresponds to the maximum of $f_\alpha(x)$, one
has necessarily $f_\alpha(x_{A'}) \leq f_\alpha(x_A)$ and thus
$r_0 f_\alpha(x_{A'}) < r_B f_\alpha(x_A)$. By
Eq.~(\ref{e:vai:eq_out_v0_small}), this implies $r_{A'} < r_A = 2m$, so
that $\Li$ emerges in the black hole region of Schwarzschild spacetime.
So none of the two possible cases (i) or (ii) leads to $\Li$ reaching
$\scri^+$. We conclude that $\Hor$ is a black hole
horizon.
\end{proof}
The black hole event horizon $\Hor$ is depicted as the thick black curve
in Fig.~\ref{f:vai:diag_S0}. Since $t_{\rm hb} < 0$ [cf. Eq.~(\ref{e:vai:t_hb})],
one immediately notices:
\begin{prop}[black hole formation in the Minkowski region]
The black hole forms in the Minkowski
region of Vaidya spacetime, i.e. in a region where the spacetime curvature
is zero.
\end{prop}
This striking feature reflects the non-local character of black holes and
will be discussed further in Chap.~\ref{s:loc}.
The dependency of $t_{\rm hb}$
on the width $v_0$ of the radiation shell is shown in Fig.~\ref{f:vai:thb_v0}.
One has $-4m < t_{\rm hb} < 0$, with
\be \label{e:vai:limit_thb_v0_0}
\lim_{v_0 \to 0} t_{\rm hb} = - 4m \qand
\lim_{v_0 \to 16m} t_{\rm hb} = 0 .
\ee
\begin{remark}
The first limit in (\ref{e:vai:limit_thb_v0_0}), which corresponds to $\alpha\to +\infty$ in Eq.~(\ref{e:vai:t_hb}),
is easily recovered by a pure geometric construction: a zero-width
shell implies the equality of the two points $A$ and $B$ considered in the
proof of (\ref{e:vai:t_hb}), as well as $t_A = t_B = - 2m$, hence
$t_C = t_{\rm hb} = - 4 m$.
\end{remark}
\begin{hist}
The imploding radiation shell with $M(v)$ piecewise linear (homothetic model)
has been extensively
studied by Achilles Papapetrou\index[pers]{Papapetrou, A.} in 1985 \cite{Papap85}.
He obtained the solution (\ref{e:vai:eq_out_v0_small}) for the outgoing radial
null geodesics and determined the location of the event horizon, along
the lines presented above.
\end{hist}
\subsection{Curvature singularity} \label{s:vai:thin:sing}
The Kretschmann scalar\index{Kretschmann scalar!of Vaidya metric}
$K := R_{\mu\nu\rho\sigma} R^{\mu\nu\rho\sigma}$
(cf. Sec.~\ref{s:sch:singularities})
is computed in the notebook~\ref{s:sam:Vaidya}:
\be \label{e:vai:Kretschmann}
K = \frac{48 M(t + r)^2}{r^6} .
\ee
$K$ is identically zero in the Minkowski region ($M(r+t) = 0$), as it should!
It diverges at $r=0$ in the radiation and Schwarzschild regions ($M(r+t) > 0$), tracing the
existence of a curvature singularity there.
In other words:
\begin{prop}[curvature singularity in Vaidya shell collapse]
The Vaidya shell collapse introduced in Sec.~\ref{s:vai:imploding_shell}
generates a spacetime with a curvature singularity
located at $r=0$ and $t \geq 0$.
\end{prop}
\begin{remark}
The Kretschmann scalar of Vaidya metric has the same structural form
as that of the Schwarzschild metric, compare Eq.~(\ref{e:sch:value_Kretschmann}),
while a priori $K$ could have
contained some term involving the derivative of $M(v)$. Indeed $M'(v)$
appears in some components of the Riemann tensor, since it is present in the
components of the Ricci tensor, as given by Eq.~(\ref{e:vai:Ricci_tensor}).
\end{remark}
\begin{remark}
Since the Ricci tensor of the Vaidya metric is not identically zero
[cf. Eq.~(\ref{e:vai:Ricci_tensor})], other curvature invariants that one might
have think of for tracking the curvature singularity are the Ricci scalar $R := g^{\mu\nu} R_{\mu\nu}$
and the Ricci ``squared'' $R_{\mu\nu} R^{\mu\nu}$. However, they are both identically zero
for $\w{k}$ is a null vector.
\end{remark}
The curvature singularity is depicted as the orange broken line in Fig.~\ref{f:vai:diag_S0},
which regards the homothetic radiation shell with $\alpha > 1/8$.
It is clear on this figure that the singularity bounds the future of both ingoing and outgoing radial null geodesics (this will be shown rigorously in Sec.~\ref{f:vai:thin_CP}).
This implies that, for $\alpha > 1/8$, the curvature singularity is \emph{spacelike},
as in Schwarzschild spacetime. We shall see in Sec.~\ref{s:vai:naked_sing} that
for $\alpha < 1/8$, the curvature singularity has a \emph{null} segment, in addition to the spacelike
one.
For the homothetic collapse with $\alpha > 1/8$ ($v_0 < 16\, m$) considered in Secs.~\ref{s:vai:sol_M_linear} and
\ref{s:vai:BH_formation} and depicted in Fig.~\ref{f:vai:diag_S0}, one has $t_{\rm hb} < 0$
[Eq.~(\ref{e:vai:t_hb})], so that
the curvature singularity is entirely located in the black hole region. It is therefore hidden
to a remote observer. In Sec.~\ref{s:vai:naked_sing}, we will see that this is no longer the
case for $\alpha < 1/8$: the singularity is then naked.
\subsection{Trapped surfaces} \label{s:vai:trapped_surf}
Let us show that there exist trapped surfaces (cf. Sec.~\ref{s:neh:trapped_surfaces}) in the
radiation and Schwarzschild regions of Vaidya spacetime.
To this aim, we consider a 2-surface $\Sp$ defined by $(t,r) = \mathrm{const}$. It is a closed surface
with the topology of a 2-sphere, spanned by the coordinates $(\th,\ph)$.
Moreover, $\Sp$ is spacelike since the metric induced by $\w{g}$ on it is
$\w{q} = r^2 \left( \dd\th^2 + \sin^2\th\, \dd\ph^2 \right) $, as readily seen
on Eq.~(\ref{e:vai:metric_IEF}). The area of $\Sp$ is simply $4\pi r^2$
($r$ is the areal radius coordinate), so to check whether $\Sp$ is a trapped surface,
it suffices to determine the behavior
of $r$ along the two null directions normal to $\Sp$, which are nothing but
the directions of the ingoing and outgoing radial null geodesics.
Along the ingoing geodesics (tangent vector $\w{k}$),
one has $\D r / \D t = - 1$, since $\w{k} = \wpar_t - \wpar_r$ [Eq.~(\ref{e:vai:k_IEF})],
so that the expansion is negative: $\theta_{(\w{k})} < 0$.
Along the outgoing radial null geodesics, $\D r / \D t$ is given by Eq.~(\ref{e:vai:ODE_outgoing_null}).
The sign of the expansion $\theta_{(\wl)}$ is then that of $r - 2M(t+r)$. Hence
\begin{prop}[trapped surfaces in Vaidya shell collapse]
\label{p:vai:trapped_surfaces}
The spherically symmetric surface $\Sp$ defined by $(t,r) = \mathrm{const}$ obeys
\be \label{e:vai:S_trapped}
\Sp \text{ is trapped} \iff r < 2M(t+r) .
\ee
Obviously, the above criterion cannot be fulfilled in the Minkowski region, where $M(t+r) = 0$.
On the contrary, trapped surfaces exist
in the central part of the radiation region, since $M(t+r) > 0$ there.
They also exist in the black hole part ($r < 2m$)
of the Schwarzschild region, where
$M(t+r) = m$.
\end{prop}
Let us denote by $\mathscr{T}$ the hypersurface formed by
all the \emph{marginally} trapped spheres
of fixed $(t,r)$ (vanishing expansion along $\wl$). The equation
of $\mathscr{T}$ is obtained by saturating the inequality
in Eq.~(\ref{e:vai:S_trapped}):
\be \label{e:vai:def_T}
\mathscr{T}:\qquad r = 2M(t + r).
\ee
As we shall see in
Chap.~\ref{s:loc}, $\mathscr{T}$ is called a
\defin{future outer trapping horizon}\index{future!outer trapping horizon}\index{trapping horizon!future!outer --}.
Equation~(\ref{e:vai:def_T}) implies $\D r / \D t = 0$ in Eq.~(\ref{e:vai:ODE_outgoing_null}),
hence we get
\begin{prop}[trapping horizon and $r$-turning points of radial null geodesics]
If an outgoing radial null geodesic $\Li$ crosses $\mathscr{T}$,
the crossing point is a $r$-turning point of $\Li$.
\end{prop}
This feature appears clearly in Figs.~\ref{f:vai:diag_S0} and \ref{f:vai:diag_S2}.
Furthermore, $\mathscr{T}$ obeys the following properties:
\begin{prop}[causal type of the future outer trapping horizon]
In the radiation region, the future outer trapping horizon $\mathscr{T}$ is a
spacelike hypersurface, while in the Schwarzschild region, $\mathscr{T}$
coincides with the event horizon $\Hor$ and hence is a null hypersurface there.
\end{prop}
\begin{proof}
Let us consider $(v,\th,\ph)$ as coordinates on the 3-manifold $\mathscr{T}$.
We may rewrite Eq.~(\ref{e:vai:def_T}) for $\mathscr{T}$ as $r = 2M(v)$, so that
$\dd r = 2M'(v) \, \dd v$ along $\mathscr{T}$.
Plugging this relation, as well as $2M(v)/r=1$, into Eq.~(\ref{e:vai:Vaidya_metric_null})
yields immediately the metric $\w{h}$ induced by $\w{g}$ on $\mathscr{T}$:
$\w{h} = 4 M'(v) \, \dd v^2
+ r^2 \left( \dd\th^2 + \sin^2\th\, \dd\ph^2 \right)$.
In $\M_{\rm rad}$, $M'(v) > 0$ [cf. Eq.~(\ref{e:vai:mass_function})], which
implies that $\w{h}$ is a positive definite metric. Hence $\mathscr{T}$
is a spacelike hypersurface in $\M_{\rm rad}$. In $\M_{\rm Sch}$, $M'(v) = 0$ and $\w{h}$
is a degenerate metric, so that $\mathscr{T}$ is a null hypersurface there.
Actually, in $\M_{\rm Sch}$, Eq.~(\ref{e:vai:def_T}) reduces
to $r = 2m$, so that $\mathscr{T}$ coincides with the event horizon $\Hor$ there.
\end{proof}
\begin{remark}
The spacelike character of $\mathscr{T}$ is actually a generic feature of future outer trapping horizons in non-stationary spacetimes (such as $(\M_{\rm rad},\w{g})$),
as we shall see in Chap.~\ref{s:loc}.
\end{remark}
\begin{figure}
\centerline{\includegraphics[width=0.6\textwidth]{vai_diag_S2.pdf}}
\caption[]{\label{f:vai:diag_S2} \footnotesize
Same as Fig.~\ref{f:vai:diag_S0}, but for the $C^2$ mass function $M(v)$
corresponding to the choice $S(x) = 6 x^5 - 15 x^4 + 10 x^3$
in Eq.~(\ref{e:vai:mass_function}) (cf. the red curve in Fig.~\ref{f:vai:mass_function}).
Note that the trapping horizon $\mathscr{T}$
(red curve) is tangent to the event horizon $\Hor$ (black curve) at the
outer edge of radiation region ($(t, r) = (m, 2m)$).
\textsl{[Figure generated by the notebook \ref{s:sam:Vaidya}]}
}
\end{figure}
For the homothetic shell model considered in Sec.~\ref{s:vai:sol_M_linear},
$M(v) = m v / v_0 = \alpha v / 2$ and the equation of
$\mathscr{T}$ in $\M_{\rm rad}$ is vey simple:
\be \label{e:vai:def_T_hom}
\mathscr{T} \cap \M_{\rm rad}:\qquad r = \alpha v .
\ee
\begin{example}
For $v_0 = 3m$, as in Fig.~\ref{f:vai:diag_S0},
$\alpha = 2/3$ and we get $r = 2v/3 = 2(t+r)/3$ or equivalently $t = r / 2$. Hence, in $\M_{\rm rad}$,
$\mathscr{T}$ appears as the straight line segment of slope $1/2$
drawn in red in Fig.~\ref{f:vai:diag_S0}.
It appears clearly there that the outgoing radial null geodesics
that cross $\mathscr{T}$ do it at a $r$-turning point.
By considering the light cones delineated by the ingoing and outgoing radial null geodesics, it
also appears
clearly on Fig.~\ref{f:vai:diag_S0} that $\mathscr{T}$ is a spacelike hypersurface in $\M_{\rm rad}$.
\end{example}
\begin{remark}
As shown above, $\mathscr{T}$ coincides with $\Hor$ in $\M_{\rm Sch}$, so that
the slope of $\mathscr{T}$ in Fig.~\ref{f:vai:diag_S0} changes abruptly from $1/2$
to $+\infty$ at the outer edge of $\M_{\rm rad}$.
This lack of smoothness of the hypersurface $\mathscr{T}$ reflects actually
the lack of smoothness of the function $M(v)$ of the homothetic shell model
(cf. the blue curve in Fig.~\ref{f:vai:mass_function}). Would $M(v)$ be smooth,
$\mathscr{T}$ would merge smoothly with $\Hor$ at $v=v_0$. This is shown in
Fig.~\ref{f:vai:diag_S2}, where $M(v)$ is of class $C^2$. Besides, we can check
on this figure that, while it has a shape more complicated
that in Fig.~\ref{f:vai:diag_S0}, $\mathscr{T}$ always lies outside the null cones in
$\M_{\rm rad}$, i.e. $\mathscr{T}$ is spacelike there.
\end{remark}
\subsection{Carter-Penrose diagram} \label{f:vai:thin_CP}
In order to draw a Carter-Penrose diagram of the Vaidya collapse,
we need first to introduce a coordinate system $(u, v, \th,\ph)$
in the radiation region $\M_{\rm rad}$ such that
$u$ is constant along the outgoing radial null geodesics ---
$v$ being constant along the ingoing ones by construction.
For the homothetic model ($M(v) = \alpha v /2$ in $\M_{\rm rad}$),
the relation between coordinates $(u, v, \th,\ph)$ and
$(v, r, \th, \ph)$ is provided by Eq.~(\ref{e:vai:eq_out_v0_small}):
\be \label{e:vai:u_lnr_v}
\encadre{ u = - \ln\left(\frac{r}{m}\right) + \ln f_\alpha\left(\frac{v}{r}\right) }.
\ee
From Eqs.~(\ref{e:vai:u_lnr_v}) and (\ref{e:vai:lnf_alpha}), we get
\[
\dd u = - \frac{1}{r} \dd r + \frac{1 - \alpha x}{\alpha x^2 - x + 2} \dd\left(\frac{v}{r}\right)
= - \frac{1}{r(\alpha x^2 - x + 2)} \left[ (\alpha x - 1) \dd v + 2 \dd r \right] .
\]
By comparing with (\ref{e:vai:self_similar_metric}), we deduce immediately
the expression of the metric tensor in terms of the coordinates $(u,v,\th,\ph)$:
\be \label{e:vai:thin:g_uv}
\w{g} = - r(\alpha x^2 - x + 2) \, \dd u \, \dd v
+ r^2 \left( \dd\th^2 + \sin^2\th\, \dd\ph^2 \right) \qquad
(0 \leq v \leq v_0) ,
\ee
where $x := v/r$ and $r$ is to be considered as a function of $(u,v)$ defined implicitly
by Eq.~(\ref{e:vai:u_lnr_v}).
Since for $\alpha > 1/8$, the polynomial $\alpha x^2 - x + 2$ never vanishes,
the metric component $g_{uv}$ read on Eq.~(\ref{e:vai:thin:g_uv}) is
nonzero in all $\M_{\rm rad}$. This shows that
the coordinates $(u,v,\th,\ph)$ are regular on $\M_{\rm rad}$
(except for the singularities inherent to the spherical coordinates $(\th,\ph)$).
Moreover, they constitute a \defin{double-null coordinate system}\index{double-null coordinates}:
both $u$ and $v$ are null coordinates. This has already been shown for $v$
(cf. Property~\ref{p:vai:null_hyp_v_const}) and for $u$, this follows from
the component $g^{uu}$ of the inverse metric deduced from (\ref{e:vai:thin:g_uv})
being identically zero
[cf. Eq.~(\ref{e:bas:char_null_coord})]. Besides,
we read on Eq.~(\ref{e:vai:thin:g_uv}) that
$g_{uu} = 0$ and $g_{vv} = 0$, which means that the coordinate vectors $\wpar_u$
and $\wpar_v$ are both null. The vector $\wpar_u$ is actually tangent to the
ingoing radial null geodesics $\Li^{\rm in}_{(v,\th,\ph)}$
and the vector $\wpar_v$ is tangent to the outgoing ones, $\Li^{\rm out}_{(u,\th,\ph)}$.
Furthermore, the null vectors $\wpar_u$
and $\wpar_v$ are both future-directed. Indeed,
the time orientation of Vaidya spacetime is given by the vector $\w{k}$
(cf. Sec.~\ref{s:vai:general}) and we deduce from Eq.~(\ref{e:vai:k_d_dr})
that $\w{k} = - (\dert{u}{r}) \, \wpar_u$. Evaluating $\dert{u}{r}$
from Eqs.~(\ref{e:vai:u_lnr_v}) and (\ref{e:vai:lnf_alpha}), we get
\be
\w{k} = \frac{2}{r(\alpha x^2 - x + 2)}\, \wpar_u .
\ee
The coefficient in front of $\wpar_u$ being always positive, we conclude that
$\wpar_u$ is future-directed. Then, from Eq.~(\ref{e:vai:thin:g_uv}),
$\w{g}(\wpar_u,\wpar_v) = g_{uv} < 0$, so that, according to Lemma~\ref{p:fra:lem2}
(Sec.~\ref{s:fra:time_orientation}), $\wpar_v$ is future-directed as well.
\begin{remark}
The reader may have noticed a slight asymmetry between the coordinates $u$
and $v$: $u$ is dimensionless, while $v$ has the dimension of a time. We could
of course make $u$ have the same dimension as $v$ by introducing an overall
factor $m$ in the right-hand side of Eq.~(\ref{e:vai:u_lnr_v}). However, this
would make the formulas slightly more complicate, without any real
benefit.
\end{remark}
Let us discuss the boundary of $\M_{\rm rad}$ in terms of the $(u,v)$ coordinates.
By definition of $\M_{\rm rad}$, a part of the boundary consists in the
hypersurfaces $v=0$ and $v = v_0$. Another part corresponds to the limit
$r\to +\infty$. In view of Eq.~(\ref{e:vai:u_lnr_v}) and $f_\alpha(0) = 1$
(cf. Eq.~(\ref{e:vai:lnf_alpha}) or Fig.~\ref{f:vai:f_alpha_x}), this corresponds
to $u \to -\infty$. The last part of the boundary of $\M_{\rm rad}$
is set by the curvature singularity at $r=0$ (cf. Sec.~\ref{s:vai:thin:sing}). Taking
the limit $r \to 0$ in Eq.~(\ref{e:vai:u_lnr_v}), we found the equation ruling
this boundary in terms of $(u,v)$:
\be \label{e:vai:thin:r_0_uv}
u = \ln\left( \frac{v_0}{v} \right) + u_0, \qquad
u_0 := \ln \sqrt{\frac{\alpha}{2}}
+ \frac{1}{\sqrt{8\alpha - 1}} \left[
\frac{\pi}{2}
+ \arctan\left( \frac{1}{\sqrt{8\alpha - 1}} \right)\right] .
\ee
We conclude that the range of the coordinates $(u,v)$ on $\M_{\rm rad}$ is