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Error when using the showRows parameter #32

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sbe1 opened this issue Nov 27, 2020 · 0 comments

sbe1 commented Nov 27, 2020 •

edited

My result rows are greater than 50, but when I use the showRows option, I get this error:

jquery-3.5.1.min.js:2 jQuery.Deferred exception: Cannot use 'in' operator to search for 'length' in 50 TypeError: Cannot use 'in' operator to search for 'length' in 50 at p (https://patentory.com/static/js/jquery-3.5.1.min.js:2:1077)
at Function.each (https://patentory.com/static/js/jquery-3.5.1.min.js:2:2937)
at i (https://patentory.com/static/js/columns/js/jquery.columns.min.js:9:2682)
at t.create (https://patentory.com/static/js/columns/js/jquery.columns.min.js:9:3166)
at t.init (https://patentory.com/static/js/columns/js/jquery.columns.min.js:9:5055)
at new t (https://patentory.com/static/js/columns/js/jquery.columns.min.js:9:5125)
at HTMLDivElement. (https://patentory.com/static/js/columns/js/jquery.columns.min.js:9:434)
at Function.each (https://patentory.com/static/js/jquery-3.5.1.min.js:2:2976)
at S.fn.init.each (https://patentory.com/static/js/jquery-3.5.1.min.js:2:1454)
at S.fn.init.e.fn.columns (https://patentory.com/static/js/columns/js/jquery.columns.min.js:9:372) undefined

If I remove the showRows option, it works fine and displays the default 5 rows. When I select 50 rows from the ui menu it also works properly.

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