/
agg.csv-spec
312 lines (260 loc) · 9.69 KB
/
agg.csv-spec
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//
// Aggs not supported by H2 / traditional SQL stores
//
singlePercentileWithoutComma
SELECT gender, PERCENTILE(emp_no, 97) p1 FROM test_emp GROUP BY gender;
gender:s | p1:d
null |10019.0
F |10099.51
M |10095.789999999999
;
singlePercentileWithComma
SELECT gender, PERCENTILE(emp_no, 97.76) p1 FROM test_emp GROUP BY gender;
gender:s | p1:d
null |10019.0
F |10099.7608
M |10096.2232
;
multiplePercentilesOneWithCommaOneWithout
SELECT gender, PERCENTILE(emp_no, 92.45) p1, PERCENTILE(emp_no, 91) p2 FROM test_emp GROUP BY gender;
gender:s | p1:d | p2:d
null |10018.745 |10018.599999999999
F |10098.0085 |10096.119999999999
M |10091.393 |10090.37
;
multiplePercentilesWithoutComma
SELECT gender, PERCENTILE(emp_no, 91) p1, PERCENTILE(emp_no, 89) p2 FROM test_emp GROUP BY gender;
gender:s | p1:d | p2:d
null |10018.599999999999 |10018.4
F |10096.119999999999 |10093.74
M |10090.37 |10086.92
;
multiplePercentilesWithComma
SELECT gender, PERCENTILE(emp_no, 85.7) p1, PERCENTILE(emp_no, 94.3) p2 FROM test_emp GROUP BY gender;
gender:s | p1:d | p2:d
null |10018.070000000002 |10018.929999999998
F |10091.343 |10098.619
M |10084.349 |10093.502
;
percentileRank
SELECT gender, PERCENTILE_RANK(emp_no, 10025) rank FROM test_emp GROUP BY gender;
gender:s | rank:d
null |100.0
F |17.424242424242426
M |15.350877192982457
;
multiplePercentileRanks
SELECT gender, PERCENTILE_RANK(emp_no, 10030.0) rank1, PERCENTILE_RANK(emp_no, 10025) rank2 FROM test_emp GROUP BY gender;
gender:s | rank1:d | rank2:d
null |100.0 |100.0
F |21.445221445221442 |17.424242424242426
M |21.929824561403507 |15.350877192982457
;
multiplePercentilesAndPercentileRank
SELECT gender, PERCENTILE(emp_no, 97.76) p1, PERCENTILE(emp_no, 93.3) p2, PERCENTILE_RANK(emp_no, 10025) rank FROM test_emp GROUP BY gender;
gender:s | p1:d | p2:d | rank:d
null |10019.0 |10018.83 |100.0
F |10099.7608 |10098.289 |17.424242424242426
M |10096.2232 |10092.362 |15.350877192982457
;
sum
SELECT SUM(salary) FROM test_emp;
SUM(salary)
---------------
4824855
;
aggregateWithCastPruned
SELECT CAST(SUM(salary) AS INTEGER) FROM test_emp;
SUM(salary)
-------------
4824855
;
aggregateWithUpCast
SELECT CAST(SUM(salary) AS DOUBLE) FROM test_emp;
CAST(SUM(salary) AS DOUBLE)
-----------------------------
4824855.0
;
aggregateWithCastNumericToString
SELECT CAST(AVG(salary) AS VARCHAR) FROM test_emp;
CAST(AVG(salary) AS VARCHAR):s
--------------------------------
48248.55
;
kurtosisAndSkewnessNoGroup
SELECT KURTOSIS(emp_no) k, SKEWNESS(salary) s FROM test_emp;
k:d | s:d
1.7997599759975997 | 0.2707722118423227
;
kurtosisAndSkewnessGroup
SELECT gender, KURTOSIS(salary) k, SKEWNESS(salary) s FROM test_emp GROUP BY gender;
gender:s | k:d | s:d
null |2.2215791166941923 |-0.03373126000214023
F |1.7873117044424276 |0.05504995122217512
M |2.280646181070106 |0.44302407229580243
;
nullAggs
SELECT MAX(languages) max, MIN(languages) min, SUM(languages) sum, AVG(languages) avg,
PERCENTILE(languages, 80) percent, PERCENTILE_RANK(languages, 3) percent_rank,
KURTOSIS(languages) kurtosis, SKEWNESS(languages) skewness
FROM test_emp GROUP BY languages ORDER BY languages ASC LIMIT 5;
max:bt | min:bt | sum:bt | avg:d | percent:d | percent_rank:d| kurtosis:d | skewness:d
---------------+---------------+---------------+--------------+---------------+---------------+---------------+---------------
null |null |null |null |null |null |null |null
1 |1 |15 |1 |1.0 |100.0 |NaN |NaN
2 |2 |38 |2 |2.0 |100.0 |NaN |NaN
3 |3 |51 |3 |3.0 |100.0 |NaN |NaN
4 |4 |72 |4 |4.0 |0.0 |NaN |NaN
;
aggByComplexCastedValue
SELECT CONVERT(CONCAT(LTRIM(CONVERT("emp_no", SQL_VARCHAR)), LTRIM(CONVERT("languages", SQL_VARCHAR))), SQL_BIGINT) AS "TEMP"
FROM "test_emp" GROUP BY "TEMP" ORDER BY "TEMP" LIMIT 20;
TEMP:l
---------------
10020
10021
10022
10023
10024
10025
10026
10027
10028
10029
100012
100025
100034
100045
100051
100063
100074
100082
100091
100104
;
aggAndOrderByCastedValue
SELECT CHAR_LENGTH(SPACE(CAST(languages AS SMALLINT))), COUNT(*) FROM test_emp GROUP BY 1 ORDER BY 1 DESC;
CHAR_LENGTH(SPACE(CAST(languages AS SMALLINT))):i| COUNT(1):l
-------------------------------------------------+---------------
5 |21
4 |18
3 |17
2 |19
1 |15
null |10
;
aggAndOrderByCastedFunctionValue
SELECT ROUND(SQRT(CAST(EXP(languages) AS SMALLINT)), 2), COUNT(*) FROM test_emp GROUP BY 1 ORDER BY 1 DESC;
ROUND(SQRT(CAST(EXP(languages) AS SMALLINT)),2):d| COUNT(1):l
-------------------------------------------------+---------------
12.17 |21
7.42 |18
4.47 |17
2.65 |19
1.73 |15
null |10
;
//
// Grouping functions
//
histogramNumeric
SELECT HISTOGRAM(salary, 5000) AS h FROM test_emp GROUP BY h;
h
---------------
25000
30000
35000
40000
45000
50000
55000
60000
65000
70000
;
histogramDate
schema::h:ts|c:l
SELECT HISTOGRAM(birth_date, INTERVAL 1 YEAR) AS h, COUNT(*) as c FROM test_emp GROUP BY h;
h | c
--------------------+---------------
null |10
1951-04-11T00:00:00Z|1
1952-04-05T00:00:00Z|10
1953-03-31T00:00:00Z|10
1954-03-26T00:00:00Z|7
1955-03-21T00:00:00Z|4
1956-03-15T00:00:00Z|4
1957-03-10T00:00:00Z|6
1958-03-05T00:00:00Z|6
1959-02-28T00:00:00Z|9
1960-02-23T00:00:00Z|7
1961-02-17T00:00:00Z|8
1962-02-12T00:00:00Z|6
1963-02-07T00:00:00Z|7
1964-02-02T00:00:00Z|5
;
histogramDateWithCountAndOrder
schema::h:ts|c:l
SELECT HISTOGRAM(birth_date, INTERVAL 1 YEAR) AS h, COUNT(*) as c FROM test_emp GROUP BY h ORDER BY h DESC;
h | c
--------------------+---------------
1964-02-02T00:00:00Z|5
1963-02-07T00:00:00Z|7
1962-02-12T00:00:00Z|6
1961-02-17T00:00:00Z|8
1960-02-23T00:00:00Z|7
1959-02-28T00:00:00Z|9
1958-03-05T00:00:00Z|6
1957-03-10T00:00:00Z|6
1956-03-15T00:00:00Z|4
1955-03-21T00:00:00Z|4
1954-03-26T00:00:00Z|7
1953-03-31T00:00:00Z|10
1952-04-05T00:00:00Z|10
1951-04-11T00:00:00Z|1
null |10
;
histogramDateWithMonthOnTop
schema::h:i|c:l
SELECT HISTOGRAM(MONTH(birth_date), 2) AS h, COUNT(*) as c FROM test_emp GROUP BY h ORDER BY h DESC;
h | c
---------------+---------------
12 |7
10 |17
8 |16
6 |16
4 |18
2 |10
0 |6
null |10
;
histogramDateWithYearOnTop
schema::h:i|c:l
SELECT HISTOGRAM(YEAR(birth_date), 2) AS h, COUNT(*) as c FROM test_emp GROUP BY h ORDER BY h DESC;
h | c
---------------+---------------
1964 |5
1962 |13
1960 |16
1958 |16
1956 |9
1954 |12
1952 |19
null |10
;
histogramNumericWithExpression
schema::h:i|c:l
SELECT HISTOGRAM(emp_no % 100, 10) AS h, COUNT(*) as c FROM test_emp GROUP BY h ORDER BY h DESC;
h | c
---------------+---------------
90 |10
80 |10
70 |10
60 |10
50 |10
40 |10
30 |10
20 |10
10 |10
0 |10
;