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2.add-two-numbers.java
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2.add-two-numbers.java
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/*
* @lc app=leetcode id=2 lang=java
*
* [2] Add Two Numbers
*
* https://leetcode.com/problems/add-two-numbers/description/
*
* algorithms
* Medium (30.54%)
* Total Accepted: 793K
* Total Submissions: 2.6M
* Testcase Example: '[2,4,3]\n[5,6,4]'
*
* You are given two non-empty linked lists representing two non-negative
* integers. The digits are stored in reverse order and each of their nodes
* contain a single digit. Add the two numbers and return it as a linked list.
*
* You may assume the two numbers do not contain any leading zero, except the
* number 0 itself.
*
* Example:
*
*
* Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
* Output: 7 -> 0 -> 8
* Explanation: 342 + 465 = 807.
*
*
*/
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) { val = x; }
* }
*/
class Solution {
public ListNode addTwoNumbers(ListNode l1, ListNode l2) {
ListNode dummy = new ListNode(0);
ListNode ptrS = dummy;
ListNode ptr1 = l1;
ListNode ptr2 = l2;
int carry = 0;
while (ptr1 != null || ptr2 != null) {
int val = carry;
if (ptr1 != null) val += ptr1.val;
if (ptr2 != null) val += ptr2.val;
if (val > 9) carry = 1;
else carry = 0;
ptrS.next = new ListNode( val % 10 );
ptrS = ptrS.next;
if (ptr1 != null) ptr1 = ptr1.next;
if (ptr2 != null) ptr2 = ptr2.next;
}
if (carry > 0) ptrS.next = new ListNode( carry );
return dummy.next;
}
}