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6_ZigZag_Conversion.go
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6_ZigZag_Conversion.go
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//package ___ZigZag_Conversion
package main
import "fmt"
/*
6. ZigZag Conversion
Medium
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The string "PAYPALISHIRING" is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)
P A H N
A P L S I I G
Y I R
And then read line by line: "PAHNAPLSIIGYIR"
Write the code that will take a string and make this conversion given a number of rows:
string convert(string s, int numRows);
Example 1:
Input: s = "PAYPALISHIRING", numRows = 3
Output: "PAHNAPLSIIGYIR"
Example 2:
Input: s = "PAYPALISHIRING", numRows = 4
Output: "PINALSIGYAHRPI"
Explanation:
P I N
A L S I G
Y A H R
P I
*/
//思路:构建一个二维数组,按照规则把符合条件的元素放到对应的位置上
func convert(s string, numRows int) string {
if s == "" || numRows <= 1 {
return s
}
// 计算二维数组所需要的列数,行数 + 对角线上的元素个数(等于行数-2) 形成一个列计算单位
maxCol := ((len(s) / (numRows + numRows - 2)) + 1) * numRows
str := make([][]string, numRows)
for i := range str {
str[i] = make([]string, maxCol)
}
ret := ""
count := 0
for i := 0; i < maxCol; i++ {
for j := 0; j < numRows; j++ {
if i%(numRows-1) == 0 || (i+j)%(numRows-1) == 0 {
str[j][i] = string(s[count])
count++
if count >= len(s) {
break
}
}
}
if count >= len(s) {
break
}
}
for i := 0; i < numRows; i++ {
for j := 0; j < maxCol; j++ {
if str[i][j] != "" {
ret += str[i][j]
}
}
}
return ret
}
func main(){
fmt.Println(convert("PAYPALISHIRING", 3))
fmt.Println(convert("PAYPALISHIRING", 4))
}