How to pass List as Extra?

[aartikov]

I want to pass List as Extra (MyType is Serializable). How can I do that?
I can use ArrayList instead of List, but I think that to use concreate implementation is not a good programming practice.

Could you please modify BundleWrapper, so it will support lists of serializable objects?

[FrantisekGazo]

Supporting just List would be tricky - e.g. if you initialized it with a custom implementation then you would expect to have it there after deserialization.

I could try to add a mechanism for custom serialization&deserialization of objects.

[FrantisekGazo]

@aartikov v2.6.0-beta1 is out.

Now you can specify your own Bundler implementation for any object field.
e.g. @Extra(MyListBundler.class) List<String> mList;

Same goes for @Arg and @State.

You can try it and give me feedback 😉

[aartikov]

Nice! It works.

This is my ListBundler:

public class ListBundler implements Bundler<List> {
	private static final String KEY = "key";

	@Override
	@SuppressWarnings("unchecked")
	public void save(@Nullable List value, @NonNull Bundle state) {
		if(value == null || value instanceof Serializable) {
			state.putSerializable(KEY, (Serializable) value);
		} else {
			state.putSerializable(KEY, new ArrayList(value));
		}
	}

	@Nullable
	@Override
	public List restore(@NonNull Bundle state) {
		return (List)state.getSerializable(KEY);
	}
}

[FrantisekGazo]

Ok, I'll just change the package name to blade.Bundler and if I don't find anything else I'll release it as 2.6.0

[FrantisekGazo]

version 2.6.0 released