Problem with ipython 8.1.0

[aroberge]

In [6]: a = [1, 2, 3]

In [7]: a[3]
venv-friendly-ipython\lib\site-packages\friendly_traceback\runtime_errors\index_error.py:110 index_out_of_range
    'node is not Subscript in index_out_of_range().' (str) len=46
venv-friendly-ipython\lib\site-packages\friendly_traceback\info_specific.py:90 _index_error
    str(value): 'list index out of range' (str) len=23
venv-friendly-ipython\lib\site-packages\friendly_traceback\utils.py:64 RuntimeMessageParser._get_cause


Traceback (most recent call last):
  Code block [7], line 1, in <cell line: 1>
    a[3]
IndexError: list index out of range

Friendly-traceback does not know the cause of this error.

When running this example using simply friendly, we have:

type(tb_data.node) = <class 'ast.Subscript'>

When running from withing IPython, we get <class 'NoneType'> instead.

[aroberge]

Doing some diagnostics, in friendly_traceback/core.py, near line 272:

        node_info = self.records[-1].node_info  # noqa
        print(f"{node_info=}")
        if node_info:
            self.node, _ignore, self.node_text = node_info
            print(f"{self.node=}, {_ignore=}, {self.node_text=}")

Using simply friendly/friendly_traceback we get

node_info=(<ast.Subscript object at 0x000001E3FCA68460>, (0, 4), 'a[3]')
self.node=<ast.Subscript object at 0x000001E3FCA68460>, _ignore=(0, 4), self.node_text='a[3]'

However, when using within IPython, we get

node_info=(None, (0, 4), 'a[3]')
self.node=None, _ignore=(0, 4), self.node_text='a[3]'

[aroberge]

One more example. When running simply IPython with the following example:

In [1]: a = [1, 2, 3]

In [2]: a[0] + a[3]
---------------------------------------------------------------------------
IndexError                                Traceback (most recent call last)
Input In [2], in <cell line: 1>()
----> 1 a[0] + a[3]

There is no highlighting of a[3].

Time for some screen captures.

[aroberge]

This now appears to be fixed.