Given an array with n objects colored red, white or blue, sort them in-place so that objects of the same color are adjacent, with the colors in the order red, white and blue.
Here, we will use the integers 0, 1, and 2 to represent the color red, white, and blue respectively.
Note: You are not suppose to use the library's sort function for this problem.
Input: [2,0,2,1,1,0] Output: [0,0,1,1,2,2]
- A rather straight forward solution is a two-pass algorithm using counting sort.
First, iterate the array counting number of 0's, 1's, and 2's, then overwrite array with total number of 0's, then 1's and followed by 2's. - Could you come up with a one-pass algorithm using only constant space?
impl Solution {
pub fn sort_colors(nums: &mut Vec<i32>) {
let mut left = 0usize;
let mut right = nums.len() - 1;
let mut index = 0usize;
while index <= right {
if nums[index] == 0 && index > left {
while left < index && nums[left] == 0 {
left += 1;
}
nums.swap(left, index);
} else if nums[index] == 2 && index < right {
while right > index && nums[right] == 2 {
right -= 1;
}
nums.swap(index, right);
} else {
index += 1;
}
}
}
}