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rotate_image.py
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rotate_image.py
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"""
48. 旋转图像
数组 数学 矩阵
中等
给定一个 n × n 的二维矩阵 matrix 表示一个图像。请你将图像顺时针旋转 90 度。
你必须在 原地 旋转图像,这意味着你需要直接修改输入的二维矩阵。请不要 使用另一个矩阵来旋转图像。
示例 1:
输入:matrix = [[1,2,3],[4,5,6],[7,8,9]]
输出:[[7,4,1],[8,5,2],[9,6,3]]
示例 2:
输入:matrix = [[5,1,9,11],[2,4,8,10],[13,3,6,7],[15,14,12,16]]
输出:[[15,13,2,5],[14,3,4,1],[12,6,8,9],[16,7,10,11]]
示例 3:
输入:matrix = [[1]]
输出:[[1]]
示例 4:
输入:matrix = [[1,2],[3,4]]
输出:[[3,1],[4,2]]
提示:
matrix.length == n
matrix[i].length == n
1 <= n <= 20
-1000 <= matrix[i][j] <= 1000
来源:力扣(LeetCode)
链接:https://leetcode-cn.com/problems/rotate-image
"""
from typing import List
class Solution:
def rotate(self, matrix: List[List[int]]) -> None:
"""
Do not return anything, modify matrix in-place instead.
"""
n = len(matrix)
for i in range(n // 2):
for j in range((n + 1) // 2):
matrix[i][j], matrix[n - j - 1][i], matrix[n - i - 1][n - j - 1], matrix[j][n - i - 1] = \
matrix[n - j - 1][i], matrix[n - i - 1][n - j - 1], matrix[j][n - i - 1], matrix[i][j]
if __name__ == '__main__':
solution = Solution()
result = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
solution.rotate(result)
print(result)
assert result == [[7, 4, 1], [8, 5, 2], [9, 6, 3]]
result = [[5, 1, 9, 11], [2, 4, 8, 10], [13, 3, 6, 7], [15, 14, 12, 16]]
solution.rotate(result)
print(result)
assert result == [[15, 13, 2, 5], [14, 3, 4, 1], [12, 6, 8, 9], [16, 7, 10, 11]]
result = [[1]]
solution.rotate(result)
print(result)
assert result == [[1]]
result = [[1, 2], [3, 4]]
solution.rotate(result)
print(result)
assert result == [[3, 1], [4, 2]]