Index on a path other than root

[blackfist]

I'm trying to find documentation on how to configure flask-autoindex to serve up a directory on a route other than /.

AutoIndex(app, browse_root='some_path')

Works and shows me the content when I visit http://localhost:5000/. I tried to do this

@app.route('/reports')
def report_path():
AutoIndex(app, browse_root='some_path')

And I get an error. What is the proper way to do what I'm trying to do?

[stephenbez]

I think this is the way to do it:

idx = AutoIndex(app, '/home/blackfist/reports', add_url_rules=False)

@app.route('/reports')
@app.route('/reports/<path:path>')
def autoindex(path='.'):
    return idx.render_autoindex(path)

I figured this out by reading the code for the AutoIndex constructor

[mrculler]

@stephenbez I'm seeing your solution get a bit closer to a working solution, but it still fails, I'm guessing because of flask-autoindex code changes since your comment here. Doing what you said makes a separately-routed autoindex work for an empty directory, but once there is a file or a subdirectory in there everything explodes.

BuildError: ('autoindex', {'path': './somefile'}, None)

I tried path.lstrip("./") and setting browse_root=False on the render_autoindex call but it nothing changed the output.

[astanway]

+1 for this feature - I also need to serve an auto index page on somewhere other than root.

[LarryKlugerDS]

The following is working for me:

files_index = AutoIndex(app, os.path.curdir + '/app/files', add_url_rules=False)
# Custom indexing
@app.route('/files')
@app.route('/files/<path:path>')
def autoindex(path='.'):
    return files_index.render_autoindex(path)

[general03]

You're right @LarryKlugerDS it's the solution !