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Understand the group theory explanation of Dirac point in graphene with the help of SpaceGroupIrep
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#11
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There are 12 irreducible representations and 12 conjugate classes belonging to Gamma point. So, how to know which operations in the little group of Gamma are selected and applied?
Why must there be two Bloch states (or bases) here?
If I understand correctly, the character of
I think you mean the following example shown in document and examples.nb: But I'm still a little confused. Take the following screenshot as an example: Here, the third column is the energy level degeneracy, and the fourth column inside curly braces is the determined LGIR, which is composed of the extended Mulliken symbol and the Gamma notation with the dimension of the representation denoted in parentheses. But the following notation is not consistent with the Mulliken symbol E_1 and E_2 in writing styles: OTOH, both E_1 and E_2 are 2 dimensional representations, the direct sum of them should give a 2+2 = 4 dimensional representation. Now, what does this mean physically? |
In principle, ALL operations should be used. But in practice, maybe after you have used several operations, the result can be determined, and then you can stop.
Because it is said that there are two pz orbitals.
The original Mulliken symbol is only defined for point group. Therefore, the BC book uses the extended Mulliken symbol, i.e., the authors extended the Mulliken symbol. E, E_1, E_2 are all 2D rep. But if this 2D rep is constructed by two 1D reps which are related by time-reversal symmetry, to differentiate the two 1D reps, the superscript 1 or 2 to the left of E is used. Refer to Tab. 5.8 of the BC book: |
The book ATOMIC and MOLECULAR SYMMETRY GROUPS and CHEMISTRY by S.C. RAKSHIT has the following description in its "APPENDIX II Character Tables of Molecular Symmetry Groups": So, if we try to find the pz orbital formed by combinations of irreducible representations, only the ones whose basis vectors and components pertinent to z should be considered. This will greatly reduce the search effort. Anyway, this is an algorithmic thing, and shouldn't be a problem solved by hand. |
Actually, the book 《群论及其在固体物理中的应用》(徐婉棠,喀兴林)also has such character tables with bases. But this works only for point group. If a problem involves energy bands, the group used should be little group, not merely point group, and the bases are actually Bloch waves, not merely the atomic-like orbitals, although in some simple cases using point group can also give correct result. |
If I understand correctly: The only thing in common is that the base is always a linear combination of a specific subset of irreducible representations, which for Bloch waves is consistent with the state superposition principle. |
Thank you for your further detailed description. I give some additional comments below. This is the so-called linear combination of atomic orbitals (LCAO) method as described here: As noted here: The basis set can either be composed of atomic orbitals (yielding the linear combination of atomic orbitals approach), which is the usual choice within the quantum chemistry community; plane waves which are typically used within the solid state community, such as the ones implemented in VASP, CASTEP, ABINIT, and Quantum ESPRESSO. Regardless of the basis set, the ultimate goal is to achieve an accurate and efficient approximate of the following famous quantum mechanics identity, as stated here: In principle, the results cannot depend on the choice of the basis. |
Yes, the ultimate goal is to solve the eigenstate |psi_i> you mentioned above, regardless of the basis set. |
But the process to solve the eigenstate |
I mean, in some cases, one have to utilize the representation matrices, not only the traces, and in these cases bases are important. Any matrix-form Hamiltonian is defined under a certain bases set, and the symmetry operation matrix (i.e. the representation matrix) operating on the Hamiltonian is also dependent on the bases set. |
This is where I get confused. Do you mean the |
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Thank you for pointing this out. There is a (self-explanatory)
OMG. I see your point: |
You are right! |
According to the following description on page 389 of the BC book: The time-reversal symmetry (TRS) only appears in complex representations. Based on my intuitive understanding, there is a close relationship between TRS and spin. |
The existence of TRS does not depend on the existence of spin. For a spinless wavefunction \psi(r), its time reversal is just its complex conjugate, i.e. \psi(r)* |
Thank you for giving a specific example to illustrate the independence between them. Your example also explains why TRS must appear in the form of paired conjugates: They always come with each other. So it's necessary to make them as a whole in the character table. |
Here's another related research about TRS, which is also the origin of my hunch that there is a close relationship between TRS and spin, as described here: However, as the PRL article above elaborated, the authors declaimed that they have found a QSH-like phase in a system where the TR symmetry is broken. The above result is consistent with the description here: |
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By the help of
SpaceGroupIrep
, I try to understand the blog here, titled "石墨烯Dirac点的群论解释", as shown below:I've obtained the SGIrepTab as follows:
But I still can't deduce the specific representation and conclusion presented in the above blog.
Any hints will be highly appreciated.
Regards,
HZ
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