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Error in lastRun() api docs. #2315


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The lastRun() api docs contain an error. Under usage, it provides the following recipe:

const { src, dest, lastRun, watch } = require('gulp');
const imagemin = require('gulp-imagemin');

function images() {
  return src('src/images/**/*.jpg', { since: lastRun(images) })

function watch() {
  watch('src/images/**/*.jpg', images);
} = watch;

However, running this gives a SyntaxError: Identifier 'watch' has already been declared. You can't name the function watch, since watch is already declared as the gulp command in de destructuring assignment.

@phated phated closed this as completed in ea52a92 Apr 27, 2019
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phated commented Apr 27, 2019

Thanks @TheDancingCode! I've rewritten it to export a default task.

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