Count ForeignKey problem

[alexsilva]

Django 1.4

qs.query.group_by = ['candidate_id', 'campaign_id']
qs = QuerySet(query=qs.query, model=self.model)  # for group by work

qs = qs.annotate(
 vote_approved=Count('candidate', only=Q(approved=True)),
 vote_analyse=Count('candidate', only=Q(approved__isnull=True)),
 vote_reproved=Count('candidate', only=Q(approved=False)),
 ultimo_voto=Max('created')
)

Sql

SELECT 
`app_bestemployee`.`id`, 
`app_bestemployee`.`voter_id`, 
`app_bestemployee`.`candidate_id`, 
`app_bestemployee`.`campaign_id`, 
`app_bestemployee`.`justification`, 
`app_bestemployee`.`justification_cancel`, 
`app_bestemployee`.`approved`, 
`app_bestemployee`.`created`, 
`app_bestemployee`.`updated`, 

MAX(`app_bestemployee`.`created`) AS `ultimo_voto`, 
COUNT(CASE WHEN `app_bestemployee`.`approved` IS NULL THEN `app_bestemployee`.`candidate_id` ELSE null END) AS `vote_analyse`, 
COUNT(CASE WHEN `app_bestemployee`.`approved` = '0'  THEN `app_bestemployee`.`candidate_id` ELSE null END) AS `vote_reproved`, 
COUNT(CASE WHEN `app_bestemployee`.`approved` = '1'  THEN `app_bestemployee`.`candidate_id` ELSE null END) AS `vote_approved` 

FROM `app_bestemployee` GROUP BY (candidate_id), (campaign_id) ORDER BY NULL

The ForeignKey count works but to seek reference in queryset have an invalid object.

qs[0].candidade -- is null

I do not know if 'aggregate-if' works in my case, but it almost solves my problems.
I would like to keep references to 'candidate' and yet count based on approved.

[henriquebastos]

What version of django and python are you using? Can you provide a PR with the failing tests?

[alexsilva]

Python 2.7
Django 1.4

Backend Mysql

The project is immense and is private, unfortunately I can not provide it.

But I passed the main part of the implementation above.