You are given an array of n+1
integers 1
through n
. In addition there is a single duplicate integer.
The array is unsorted.
An example valid array would be [3, 2, 5, 1, 3, 4]
. It has the integers 1
through 5
and 3
is duplicated. [1, 2, 4, 5, 5]
would not be valid as it is missing 3
.
You should return the duplicate value as a single integer.
def find_dup(arr):
pass
def find_dup(arr):
return [n for n in arr if arr.count(n) != 1][0]