programmers/number/make_min_num.ipynb

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  {
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   "metadata": {},
   "source": [
    "# 최솟값 만들기"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "## 문제 링크"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "* https://programmers.co.kr/learn/courses/30/lessons/12941"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "## 코드"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "시간 초과"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "metadata": {},
   "outputs": [],
   "source": [
    "def get_min_num(A, B, S, min_S):\n",
    "    if not A or not B:\n",
    "        return min(S, min_S)\n",
    "    \n",
    "    for a in A:\n",
    "        for b in B:\n",
    "            new_A, new_B = A[:], B[:]\n",
    "            new_A.remove(a)\n",
    "            new_B.remove(b)\n",
    "            \n",
    "            S += a * b\n",
    "            min_S = get_min_num(new_A, new_B, S, min_S)\n",
    "            S -= a * b\n",
    "            \n",
    "    return min_S\n",
    "\n",
    "def solution(A, B):\n",
    "    return get_min_num(A, B, S=0, min_S=float('inf'))"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "성공"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 19,
   "metadata": {},
   "outputs": [],
   "source": [
    "def get_min_num(A, B):\n",
    "    return sum([a * b for a, b in zip(sorted(A), sorted(B, reverse=True))])\n",
    "\n",
    "def solution(A, B):\n",
    "    return get_min_num(A, B)"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "### 시간 복잡도"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "metadata": {},
   "outputs": [],
   "source": []
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "## 예제"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 21,
   "metadata": {
    "scrolled": false
   },
   "outputs": [
    {
     "data": {
      "text/plain": [
       "29"
      ]
     },
     "execution_count": 21,
     "metadata": {},
     "output_type": "execute_result"
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   ],
   "source": [
    "A, B = [1, 4, 2], [5, 4, 4]\n",
    "solution(A, B)"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 22,
   "metadata": {},
   "outputs": [
    {
     "data": {
      "text/plain": [
       "10"
      ]
     },
     "execution_count": 22,
     "metadata": {},
     "output_type": "execute_result"
    }
   ],
   "source": [
    "A, B = [1, 2], [3, 4]\n",
    "solution(A, B)"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "## 참조\n",
    "\n",
    "* https://excelsior-cjh.tistory.com/40"
   ]
  }
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