[Question] How to get the difference between two dates as "N year, N months, N days"?

[KidyasoVasiliy]

Hello.
I have a function to get the period, but the problem is only days in a month.
Example

The documentation briefly describes diff, and as I understand it, you can't return the duration, only in a specific unit format
https://day.js.org/docs/en/display/difference

I want to get duration in the context of dates in which this period is specified.

Duration plugin, works without context, it doesn't fit
See issue

Who can help with this issue? Thx

[iamkun]

You can pass a unit as the second argument to get this diff in month or year

[stebogit]

@KidyasoVasiliy try this:

const date1 = dayjs('2019-04-25')
const date2 = dayjs('2020-09-14')
const d = Math.abs(date1.diff(date2, 'day') % 365)
const m = Math.abs(date1.diff(date2, 'month') % 12)
const y = Math.abs(date1.diff(date2, 'year'))
console.log(`${y} year(s), ${m} month(s) and ${d} day(s)`) // 1 year(s), 4 month(s) and 143 day(s)

[KidyasoVasiliy]

@KidyasoVasiliy try this:

const date1 = dayjs('2019-04-25')
const date2 = dayjs('2020-09-14')
const d = Math.abs(date1.diff(date2, 'day') % 365)
const m = Math.abs(date1.diff(date2, 'month') % 12)
const y = Math.abs(date1.diff(date2, 'year'))
console.log(`${y} year(s), ${m} month(s) and ${d} day(s)`) // 1 year(s), 4 month(s) and 143 day(s)

Thank you, this is almost what me need, but it still counts without period context. That is, high year is not taken into account - leap year