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0399.evaluate-division

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题目

Equations are given in the format A / B = k, where A and B are variables represented as strings, and k is a real number (floating point number). Given some queries, return the answers. If the answer does not exist, return -1.0.

Example:

Given  a / b = 2.0, b / c = 3.0. queries are:  a / c = ?,  b / a = ?, a / e = ?,  a / a = ?, x / x = ? . return  [6.0, 0.5, -1.0, 1.0, -1.0 ].

The input is:  vector<pair<string, string>> equations, vector<double>& values, vector<pair<string, string>> queries , where equations.size() == values.size(), and the values are positive. This represents the equations. Return  vector<double>.

According to the example above:
equations = [ ["a", "b"], ["b", "c"] ],
values = [2.0, 3.0],
queries = [ ["a", "c"], ["b", "a"], ["a", "e"], ["a", "a"], ["x", "x"] ].

The input is always valid. You may assume that evaluating the queries will result in no division by zero and there is no contradiction.

解题思路

见程序注释