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15 - 三数之和 #8

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jack-pearson opened this issue Feb 24, 2022 · 1 comment
Open

15 - 三数之和 #8

jack-pearson opened this issue Feb 24, 2022 · 1 comment

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@jack-pearson
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jack-pearson commented Feb 24, 2022

给你一个包含 n 个整数的数组 nums,判断 nums 中是否存在三个元素 a,b,c ,使得 a + b + c = 0 ?请你找出所有和为 0 且不重复的三元组。

注意:答案中不可以包含重复的三元组。

示例 1:

输入:nums = [-1,0,1,2,-1,-4]
输出:[[-1,-1,2],[-1,0,1]]

示例 2:

输入:nums = []
输出:[]

示例 3:

输入:nums = [0]
输出:[]

提示:
0 <= nums.length <= 3000
-105 <= nums[i] <= 105

@jack-pearson
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function threeSum(nums: number[]): number[][] {
  const result: number[][] = [];
  const len = nums.length;
  if (len < 3) return result;
  nums.sort((a, b) => a - b);
  for (let i = 0; i < len - 2; i++) {
    if (nums[i] > 0) break;
    if (i > 0 && nums[i] === nums[i - 1]) continue;
    let l = i + 1;
    let r = len - 1;
    while (l < r) {
      const sum = nums[i] + nums[l] + nums[r];
      if (sum === 0) {
        result.push([nums[i], nums[l], nums[r]]);
        while (l < r && nums[l] === nums[l + 1]) l++;
        while (l < r && nums[r] === nums[r - 1]) r--;
        l++;
        r--;
      } else if (sum < 0) {
        l++;
      } else {
        r--;
      }
    }
  }
  return result;
}

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